wywołanie metody kwadrat

Pytania dotyczące zadania

Kwadrat liczby

Składnia Java, Poziom 1, Lekcja 8

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Chciałbym zrozumieć, dlaczego można najpierw wywołać metodę kwadrat, a dopiero poniżej ją zdefiniować?

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Guadalupe Gagnon

Poziom 37 , Tampa, United States

15 czerwca 2021, 14:08

I don't understand your question without having example code of what you are talking about, but I will try to answer Java pre-loads class data, such as fields and methods, at run time. So, unlike a language like C or Python, it matters not where the code is defined, just as long as it does exist. You can shuffle the order of all the fields, methods, constructors of a class and it will still function exactly the same.

Guadalupe Gagnon

Poziom 37 , Tampa, United States

15 czerwca 2021, 14:15

Take these two classes as an example. While they are structured different they are functionally identical. This is because they both have the same methods/fields/constructors (I didn't code in a constructor here but that would mean they both have a default constructor):

class Test {
   static int field1 = 5;
   static int field2 = 7;

   static void printField1() {
      System.out.println(field1);
   }

   static void printField2() {
      System.out.println(field2);
   }

   static void printAllFields() {
      System.out.println(field1 + " " + field2);
   }

   public static void main(String[] args) {
      printField1();
      printField2();
      printAllFields();
   }
}

class Test {
   static void printField2() {
      System.out.println(field2);
   }

   static int field1 = 5;

   static void printField1() {
      System.out.println(field1);
   }

   public static void main(String[] args) {
      printField1();
      printField2();
      printAllFields();
   }

   static void printAllFields() {
      System.out.println(field1 + " " + field2);
   }

   static int field2 = 7;
}