Code does not match the requirements

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In der Diskussion

package de.codegym.task.task04.task0424; /* Drei Zahlen */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { BufferedReader eingabe = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(eingabe.readLine()); int b = Integer.parseInt(eingabe.readLine()); int c = Integer.parseInt(eingabe.readLine()); if (a==b && a != c){ System.out.println(c); } else if (a==c&& a != b){ System.out.println("b"); } else if (b==c&& b!=a){ System.out.println(a); } } }

Kommentare (6)

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Christophsnz

Level 9 , Germany, Netherlands

23 August 2021, 12:05

ich kann dir leider nicht ganz folgen ^^

Thomas

Level 41 , Bayreuth, Germany

23 August 2021, 12:42

you could try smth. like that

if (a == b && a != c) {
    System.out.println(3);
} else if (a == c && a != b) {
    System.out.println(2);
} else if (b == c && b != a) {
    System.out.println(1);
}

// or
if (!(a == b && b == c))
    if (a == b)
        System.out.println(3);
    else if (a == c)
        System.out.println(2);
    else
        System.out.println(1);

Christophsnz

Level 9 , Germany, Netherlands

23 August 2021, 11:26

Thank you Thomas, but my Code doesnt meet the requirements so far - any hints?

Thomas

Level 41 , Bayreuth, Germany

23 August 2021, 11:52

yes, you need to output the ordinal, not "b" or the value of some variable. The ordinal of the first number you enter is 1, for the second it is 2 and so on. Something similar to an index.

Christophsnz

Level 9 , Germany, Netherlands

23 August 2021, 07:59

Why do I need a comparison for not equal?

Thomas

Level 41 , Bayreuth, Germany

23 August 2021, 08:46

cause of the fourth requirement: • If all the numbers are different, don't display anything. if you just check for eg. a == b then c could be equal to a and b as well but you'd output c's index as ordinal