I don't understand

Frage zur Aufgabe

In der Diskussion

I cant get the new entered numbers to be added to the existing sum which obviously is 0 at the start. Hope to get some help here. thanks guys.

public class Solution {
    public static void main(String[] args) throws Exception {
        //schreib hier deinen Code

    int x = 0;
    int y = 0;

    while (true){

    BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
    String s = reader.readLine();
    int x = Integer.parseInt(s);

    if (x == -1);
    break;

    else (y= y+x);
    }
    System.out.println(y-1);
    }
}

Gib über die Tastatur Zahlen ein.
Wenn der Benutzer -1 eingibt, zeige die Summe aller eingegebenen Zahlen an und beende das Programm.
-1 muss in der Summe enthalten sein.

Tipp: Eine der Lösungen für dieses Problem verwendet das folgende Konstrukt:

while (true) {
    int zahl = Zahl einlesen;
    if (prüfen, ob die Zahl -1 ist)
        break;
}

Anforderungen:

Das Programm muss die Zahlen von der Tastatur einlesen.
Wenn der Benutzer -1 eingibt, muss das Programm die Summe aller eingegebenen Zahlen anzeigen und sich dann beenden.
Das Programm muss die Summe der eingegebenen Zahlen berechnen und anzeigen.
Das Programm muss eine for-Schleife oder eine while-Schleife verwenden.

package de.codegym.task.task04.task0442; /* Addieren */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //schreib hier deinen Code int x = 0; int y = 0; while (true){ BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); String s = reader.readLine(); int x = Integer.parseInt(s); if (x == -1); break; else (y= y+x); } System.out.println(y-1); } }

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Guadalupe Gagnon

Level 37 , Tampa, United States

11 Juli 2022, 15:08

Some problems preventing this code from compiling: #1 line 21: This line is declaring an int, 'x', however there is already a variable named 'x' on line 14. In Java you can not have two local variables (or two class variables) with the same name in the same block of code. #2 line 23: There is a semi colon following the 'if' statement. This means that nothing will be processed if that is true. It would be the same exact as this:

if (x == -1) {
   // empty
}
break;
else y= y+x; // unreachable

With that the next line, 'break;', is by itself and the following line, 'else y= y+x;', is unreachable since the 'break' is reached every loop cycle as it is not behind a logic gate. Since the 'else' is not connected to the 'if' it is an illegal statement as well, but that will be fixed by removing the errant semi colon. = = = = = The code should pass when those are fixed.

Ch1psta

Level 6

11 Juli 2022, 19:21

I actually fixed the code on a later task when I saw the semi colon in line 23. It was only that as far as I now remember from the top of my head.