How can I use the method "min(int a, int b)" ?

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package com.codegym.task.task02.task0217;

/*
Minimum of four numbers

*/
public class Solution {
    public static int min(int a, int b, int c, int d) {
        //write your code here
       int r ;
       if((a<=b)&&(a<=c)&&(a<=d) )
            r=a;
       else if((b<=a)&&(b<=c)&&(b<=d))
            r=b;
       else if ((c<=a)&&(c<=b)&&(c<=d))
            r=c;
       else
            r=d;
 return r;



    }

    public static int min(int a, int b) {
        //write your code here

            if(a<b)
              return a;
             else
              return b;

    }

    public static void main(String[] args) throws Exception {
        System.out.println(min(-20, -10));
        System.out.println(min(-20, -10, -30, -40));
        System.out.println(min(-20, -10, -30, 40));
        System.out.println(min(-40, -10, -30, 40));
    }
}

Write a function that computes the minimum of four numbers.
The function min(a, b, c, d) should use (call) the function min(a, b)

Hint:
You need to write the body of the two existing min functions.

Requirements:

The program should display text on the screen.
The min methods should not display text on the screen.
The main method should call min(a, b) and min(a, b, c, d).
The main method should display the result of the min methods. Each time, on a new line.
The min(a, b) method must return the minimum of the numbers a and b.
The min(a, b, c, d) method must use the min(a, b) method.
The min(a, b, c, d) method must return the minimum of the numbers a, b, c, and d.

package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { //write your code here int r ; if((min(int a,int b)<=a)&&(a<=c)&&(a<=d) ) r=a; else if((b<=a)&&(b<=c)&&(b<=d)) r=b; else if ((c<=a)&&(c<=b)&&(c<=d)) r=c; else r=d; return r; } public static int min(int a, int b) { //write your code here if(a<b) return a; else return b; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

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Theresa Secore

Level 4 , Commerce City, United States

9 June 2020, 22:06

You're calling a method within a method, since you'll have already written the logic for method: min(int a, int b), in your 'min' method with 4 int parameters, call on the min method with 2 parameters - another words, you're using 'min' method with 2 parameters do the work for you to compare a & b

Ryan

Level 16 , Ashburn, United States

27 May 2020, 18:13

Your 2 parameter (a & b) method looks right. For the 4 parameter (a, b, c, & d) method the if/else is not needed for this. Think about how the 2 parameter min method is used (giving you the min number of two numbers) and you will be able to solve this by calling the 2 parameter method 3 times within the 4 parameter method. You can call the 2 parameter method in the 4 parameter method by declaring a int variable and initializing it to the min method (e.g. int m1 = min(a, b);).

Ashish RajAnand

Level 13 , Bhilai , India

26 May 2020, 07:44

lets see this if You have two number a=7,b=9 so we can use min(a,b) if you have three number a=6,b=7,c=8 here is trick int x=min(a,b) //here we got min of a,b is x we use again min(x,c) //here finally got minimum I think better to do for four number .