Struggling with the logic part of this question.

Question about the task

Resolved

I am getting an output of 0000 and I am not sure what I am doing wrong. while (true) { int n=Integer.parseInt(cbeu.readLine()); if (n==-1) { sum+=n; break; } System.out.print(sum);

Use the keyboard to enter numbers.
If the user enters -1, display the sum of all entered numbers and end the program.
-1 should be included in the sum.

Hint: one of the solutions to this problem uses the following construct:

while (true) {
    int number = read the number;
    if (check whether the number is -1)
        break;
}

Requirements:

The program should read the numbers from the keyboard.
If the user enters -1, the program should display the sum of all entered numbers and then end.
The program must calculate and display the sum of the entered numbers.
The program must use a for loop or a while loop.

package com.codegym.task.task04.task0442; /* Adding */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { BufferedReader cbeu=new BufferedReader(new InputStreamReader(System.in)); //write your code here int sum=0; while (true) { int n=Integer.parseInt(cbeu.readLine()); if (n==-1) { sum+=n; break; } System.out.print(sum); } } }

Comments (3)

Popular
New
Old

You must be signed in to leave a comment

BLANC

Level 12 , Paris, France

28 May 2020, 08:07

hi, here my solution : BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); int sum=0; while (true) { String sNumber = reader.readLine(); int number = Integer.parseInt(sNumber); sum = sum + number; if (number==-1) break; } System.out.println(sum); } }

AnnemiekFF

Level 41 , Breda, Netherlands

28 May 2020, 06:57

Why do you only add n to the sum if n = -1?

Gellert Varga

Level 23 , Szekesfehervar, Hungary

27 May 2020, 13:01

solution

I attach a screenshot. This is your code, just in a more readable layout. If you are trying to write "clean code", you will also have a better understanding of what is happening in the program.