Have been trying for days.. Can't figure it out...

Question about the task

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Help is greatly appreciated!

1. Create a list of numbers.
2. Use the keyboard to add 10 numbers to the list.
3. Display the length of the longest sequence of repeating numbers in the list.

Example for the list 2, 4, 4, 4, 8, 8, 4, 12, 12, 14:
3

The value is 3, because the longest sequence of repeating numbers is three fours.

Requirements:

The program must display a number on the screen.
The program should read values from the keyboard.
In the main method, declare an ArrayList variable with Integer elements and immediately initialize it.
The program should add 10 numbers to the collection in accordance with the conditions.
The program should display the length of the longest sequence of repeating numbers in the list.

package com.codegym.task.task08.task0812; import java.io.*; import java.util.ArrayList; import java.util.Collections; /* Longest sequence */ public class Solution { public static void main(String[] args) throws IOException { ArrayList<Integer> numbers = new ArrayList<>(); BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); for (int i = 0; i < 10; i++) { numbers.add(Integer.parseInt(reader.readLine())); } int counter = 1; int finalNum = 1; for (int i = 0; i < numbers.size() - 1; i++) { if (numbers.get(i).equals(numbers.get(i + 1))) counter++; if (!numbers.get(i).equals(numbers.get(i + 1))) { if (counter > finalNum) { counter = 1; } } } if (counter > finalNum) finalNum = counter; System.out.println(finalNum); } }

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Thomas

Level 41 , Bayreuth, Germany

6 July 2020, 09:48

The check you do in line 28 should be done within your first if condition right after counter++;