not satisfies 3rd and 4th condition

Question about the task

Checking the order

Java Syntax, Level 7, Lesson 9

Under discussion

my code gives output correct

1. Read 10 words from the keyboard and add them to a list of strings.
2. Determine whether the list is ordered by increasing string length.
3. If it is not, then display the index of the first element that violates this order.

Requirements:

Declare a string list variable and immediately initialize it.
Read 10 lines from the keyboard and add them to the list.
If the list is ordered by increasing string length, then you don't need to display anything.
If the list is not ordered by increasing string length, then display the index of the first element that violates this order.

package com.codegym.task.task07.task0718; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.*; /* Checking the order */ public class Solution { public static void main(String[] args) throws IOException { Scanner in = new Scanner(System.in); ArrayList<String> list =new ArrayList<String>(); for(int i = 0;i < 10;i++){ list.add(in.next()); } for(int i = 0;i < list.size()-1;i++){ if(list.get(i).length() > list.get(i+1).length()){ System.out.println(i+1); break;} } } }

Comments (2)

Popular
New
Old

You must be signed in to leave a comment

Riya

Level 15 , Indore, India

19 July 2020, 02:57

still having issue

Dawid

Level 28

18 July 2020, 20:56

So if for example 1st and 2nd elements are equal thats violates rules and by your program logic it does not violate. I propose:

for (int j = 0; j < list.size(); j++) {
            if (list.get(j).length() < list.get(j + 1).length()) {

            } else {
                System.out.println(j + 1);
                break;
            }
        }