package com.codegym.task.task08.task0815;
import java.util.HashMap;
import java.util.HashSet;
/*
Census
The getSameLastNameCount() method must return the number of people whose last name is the same as the lastName parameter.
*/
public class Solution {
public static HashMap<String, String> createMap() {
HashMap<String, String> map = new HashMap<String, String>();
map.put("A","E1");
map.put("Ab","E2");
map.put("Abc","E3");
map.put("Abcd","E4");
map.put("Abcde","E6");
map.put("Abcdef","E5");
map.put("Abcdefg","E8");
map.put("Abcdefgh","E9");
map.put("Abcdefghj","E10");
map.put("Abcdefghjk","E11");
return map;
}
public static int getSameFirstNameCount(HashMap<String, String> map, String Name) {
int count =0;
for (HashMap.Entry <String,String>pair:map.entrySet()) {
if(pair.getKey().equals(Name))count++;
}
return count;
}
public static int getSameLastNameCount(HashMap<String, String> map, String lastName) {
int count =0;
for (HashMap.Entry <String,String>pair:map.entrySet()) {
if(pair.getKey().equals(lastName))count++;
}
return count;
}
public static void main(String[] args) {
}
}
how do is pass the getSameFirstNameCount requirement
Under discussion
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Nouser
21 August 2020, 07:25
the value of the map entry is the first name
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