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Write a function that computes the minimum of four numbers.
The function min(a, b, c, d) should use (call) the function min(a, b)

Hint:
You need to write the body of the two existing min functions.

Requirements:

The program should display text on the screen.
The min methods should not display text on the screen.
The main method should call min(a, b) and min(a, b, c, d).
The main method should display the result of the min methods. Each time, on a new line.
The min(a, b) method must return the minimum of the numbers a and b.
The min(a, b, c, d) method must use the min(a, b) method.
The min(a, b, c, d) method must return the minimum of the numbers a, b, c, and d.

package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { int m2; if ( m1 <= c && m1 <= d){ m2 = m1; } else if ( c <= m1 && c <= d){ m2 = c; } else { m2 = d; } return m2; } public static int min(int a, int b) { int m1; if ( a <= b){ m1 = a; } return m1; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

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143_Ritik Awachat

Level 4

16 September 2020, 04:05

thanks both of you

Hang Do

Level 13 , Hanoi, Viet Nam

15 September 2020, 16:02

useful

To compare a, b, c, d: - compare a and b first: write the function calMin(a, b), this function return min of a and b, assigned to variable min (integer) - next, compare the above min variable with c, using the function calMin above, this time call it as callMin(min, c). The result of this call is assign to variable min again. - finally, compare min with d, by calling calMin(min, d), the final result is assign to min. Print this min variable. Done. So briefly, you just need to write function calMin to find the min between 2 numbers.

horst

Level 26 , Not in list

15 September 2020, 13:08

useful

I'm sorry to say but you will have to rework both of your min-functions. Let's start with the smaller one (two parameters): You are currently setting an "empty" int variable called "m1" and you return it if b is bigger than a. Instead, your method should obviously return b in this case. My advice is: keep it simple: If (a <= b) return a, else return b - no need for "m1" :) The bigger min-function (four parameters) works in a similar way. Just as a tip: you can use the smaller min-function inside the body of the bigger min-function, roughly like this: if (min(a,b) <= min(c,d)) return the minimum of a and b, else return the minimum of c and d.