How value is being passed

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How does the java compiler knows that i have to hold 41 as value in this method--> public static double convertCelsiusToFahrenheit(int celsius) what is the rule behind that every time i get confused in programs when i see this please make me clear.

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Stephen Haokip

Level 13

18 October 2020, 14:09

suppose i have a method public static int add(int a, int b){ return a+b; } now i call that method by writing the name of the method and the parameters in brackets like this add(5, 8);

Stephen Haokip

Level 13

18 October 2020, 08:17

your question is confusing

Dinesh

Level 7 , Delhi, India

18 October 2020, 08:34

Please refer the code. Now it might be helpful to overcome your confusion. public class Solution{ public static void main(String[] args) { System.out.println(convertCelsiusToFahrenheit(41)); } public static double convertCelsiusToFahrenheit(int celsius) { //write your code here double TF=9/5.0*celsius+32; return TF; } }