Hey again, I tried to initialize, but-- WHY WON'T IT WORK...?!

Question about the task

Longest string

Java Syntax, Level 7, Lesson 6

Under discussion

I tried to initialize... but look...!!!?!?!?!!!!!!!!!!

1. Initialize the list of strings.
2. Read 5 strings from the keyboard and add them to this list.
3. Using a loop, find the longest string in the list.
4. Display the string. If there is more than one, display each on a new line.

Requirements:

In the main method, initialize the Solution class's existing strings field to a new ArrayList<>.
The program should read 5 strings from the keyboard and write them to the list of strings.
The program should display the longest string.
If several strings qualify as the longest, then you need to display each of them on a new line.

package com.codegym.task.task07.task0708; import java.io.BufferedReader; import java.io.InputStreamReader; import java.util.ArrayList; import java.util.List; /* Longest string */ public class Solution { private static List<String> strings; strings.add("0"); strings.add("0"); strings.add("0"); strings.add("0"); strings.add("0"); public static void main(String[] args) throws Exception { //write your code here BufferedReader inp = new BufferedReader (new InputStreamReader(System.in)); for (int i = 0; i < 5; i++) { String T= inp.readLine(); // for taking a number as an input strings.add(i, T.toString()); } System.out.println(strings.get(0)); } }

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Misiu

Level 41 , Gdansk, Poland

19 November 2020, 01:09

- lines 15-19 don't work (even when list is initialized). Methods may be invoked from other methods (constructors) or initializing blocks. - index in method add() (line 27) is not needed. Elements in lists are added in order of entering them, from index 0. - names of variables should begin with small character.

Cam

Level 15 , Bogota, Colombia

19 November 2020, 00:07

remember that initializing does not necessarily mean filling with data. It means telling the computer what kind of data your variable will store (in this case you are creating a new List)

Misiu

Level 41 , Gdansk, Poland

18 November 2020, 20:05

Here initialize means: create object. In line 14 there is a variable that will store a list. But the list doesn't exists. So you can't to add something to non existing object.