code not compiling

Question about the task

Day of the week

Java Syntax, Level 4, Lesson 4

Under discussion

This code is indicating error at the point of reader.readLine() method, I can't see any visible error.

Use the keyboard to enter a number representing a day of the week. Then, depending on the entered number, display the name of the day of the week: "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday", if you enter a number greater than 7 or less than 1, display "No such day of the week".

Example for number 5:
Friday

Example for number 10:
No such day of the week

Requirements:

The program should read a number from the keyboard.
The program should display text on the screen.
If you enter a number from 1 to 7, you need to display the name of the day of the week.
If you enter a number outside the range of 1 to 7, then display a notification that there is no such day of the week.

package com.codegym.task.task04.task0413; /* Day of the week */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); String day =Integer.parseInt(reader.readLine()); switch(day) { case 1 : System.out.println("Monday"); break; case 2:System.out.println("Tuesday"); break; case 3: System.out.println("Wednesday"); break; case 4: System.out.println("Thursday"); break; case 5: System.out.println("Friday"); break; case 6: System.out.println("Saturday"); break; case 7: System.out.println("Sunday"); break; default: System.out.println("No such day of the week"); break; } //write your code here } }

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Sunaina Yadav QA Engineer at Ness Technologies

3 January 2021, 16:34

String day =Integer.parseInt(reader.readLine()); Issue is with this line. Task says: Use the keyboard to enter a number representing a day of the week. So above line should be int day=Integer.parseInt(reader.readLine());

Constantin Anton

Level 7 , Coventry, United Kingdom

2 January 2021, 14:21

Line 13, day is not a string but an integer.

Nouser

Level 36 , Germany

30 December 2020, 08:25

You try to assign an Integer to a String So either you could change the variable type in line 13 or don't parse the input for a integer but therefore change the case clauses to accept a string.