Problem with test case 3 - min(-20, -10, -30, -40)

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My code is almost complete, however I am having an issue with the above stated test case. How can I fix it? package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { //write your code here int minNum = min(a,b); if (a < minNum){ return a; } else if (b < minNum){ return b; } else if (c < minNum){ return c; } else if (d < minNum){ return d; }else return minNum; } public static int min(int a, int b) { //write your code here int min1 = (a < b) ? a : b; return min1; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

Write a function that computes the minimum of four numbers.
The function min(a, b, c, d) should use (call) the function min(a, b)

Hint:
You need to write the body of the two existing min functions.

Requirements:

The program should display text on the screen.
The min methods should not display text on the screen.
The main method should call min(a, b) and min(a, b, c, d).
The main method should display the result of the min methods. Each time, on a new line.
The min(a, b) method must return the minimum of the numbers a and b.
The min(a, b, c, d) method must use the min(a, b) method.
The min(a, b, c, d) method must return the minimum of the numbers a, b, c, and d.

package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { //write your code here int minNum = min(a,b); if (a < minNum){ return a; } else if (b < minNum){ return b; } else if (c < minNum){ return c; } else if (d < minNum){ return d; }else return minNum; } public static int min(int a, int b) { //write your code here int min1 = (a < b) ? a : b; return min1; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

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Nouser

Level 36 , Germany

27 January 2021, 10:45

or, as you already have the min of a and b

int minAB = min(a, b);

why not get the min of c and d

int minCD = min(c, d);

as last step just get the min of minAB and minCD

Johnnatan Romero

Level 14 , Petawawa, Canada

27 January 2021, 02:58

Hi with your min() you already know which one is min between a and b. I would not use it again in min method. I would use just c and d. Ex:

if(c < minNum){
...}else if{
...}else{
...}