need some hint

Question about the task

Even and odd digits

Java Syntax, Level 6, Lesson 5

Under discussion

hint please

Use the keyboard to enter a positive number. Determine the number of even digits and odd digits in the entered number.
If a number is divisible by 2 without a remainder (i.e. the remainder is zero), then it is even.
And we'll increase the even digit counter (static variable even) by 1.
Otherwise, the number is odd, so we'll increase the odd digit counter (static variable odd).
Display the following message: "Even: a Odd: b", where a is the number of even digits and b is the number of odd digits.

Example for 4445:
Even: 3 Odd: 1

Requirements:

The program must read data from the keyboard.
The main method should calculate how many even digits are in the entered number and then write this number to the variable even.
The main method should calculate how many odd digits are in the entered number and then write this number to the variable odd.
The program should display text on the screen.
The displayed text must match the task conditions.

package com.codegym.task.task06.task0606; import java.io.*; /* Even and odd digits */ public class Solution { public static int even=0; public static int odd=0; public static void main(String[] args) throws IOException { BufferedReader rid = new BufferedReader(new InputStreamReader(System.in)); int num = Integer.parseInt(rid.readLine()); if(num%2==0){ even++; } else if(num%2!=0){ odd++; } System.out.println("Even: " + even + " Odd: " + odd); //write your code here } }

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Swati

Level 8 , Pune, India

5 January 2019, 09:23

hii, whatever no.u entered that should be greater than 0.you have check this. then everytime.create 1 temporary variable which can store the remainder after dividing by 10. like this: temp = n % 10 then everytime divide the no.by 10 and store it in variable like this: n = n / 10 then check if temp%2 == 0 for else u don't need to check any condition...just increement odd counter. and everytime u have divide no.by 10.so that u can check every digit comes in whole no.(if 4 digit or 3 digit)

Guadalupe Gagnon

Level 37 , Tampa, United States

5 January 2019, 03:44

use a structure like this:

while (number > 0){

int singleDigit = number %10;

// Enter code here to check digit

number /= 10;

}