Compiles even gives the null exeption requested on the requirements, still does not pass the verification, 100 attempst I quit...

Question about the task

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Read from the console to extend the functionality by analogy:
1. Figure out what the program does.
2. All classes must be inside the Solution class.
3. Add Cartoon and Thriller classes.
4. Understand how we get a SoapOpera object using the key "soapOpera".

Following the pattern used to obtain a SoapOpera object:
5. Add to MovieFactory.getMovie the ability to get a Cartoon object using the key "cartoon".
6. Add to MovieFactory.getMovie the ability to get a Thriller object using the key "thriller".
7. Read several keys (strings) from the console.
7.1. Stop reading in strings as soon as a string is entered that does not match one of the following: "cartoon", "thriller", "soapOpera".
8. Create a Movie movie variable, and for each entered string (key):
8.1. Get an object using MovieFactory.getMovie and assign it to the variable movie.
8.2. Display the result of calling movie.getClass().getSimpleName().

Requirements:

The Cartoon and Thriller classes must be static and be located inside the Solution class.
The MovieFactory.getMovie method must return a Cartoon object if "cartoon" is passed as an argument.
The MovieFactory.getMovie method must return a Thriller object if "thriller" is passed as an argument.
The main method must read strings from the keyboard.
The main method should stop reading strings from the keyboard if an invalid string is entered (i.e. something other than "cartoon", "thriller", or "soapOpera").
For each string entered (including the invalid string), you must call the MovieFactory.getMovie method.
For each valid string entered, you need to display the simple name (movie.getClass().getSimpleName()) of the object types returned by the MovieFactory.getMovie method.

package com.codegym.task.task14.task1414; import java.util.ArrayList; import java.io.*; /* MovieFactory */ public class Solution { public static void main(String[] args) throws Exception { ArrayList<Movie> cinema = new ArrayList<Movie>(); BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); while (true){ String s = reader.readLine(); if (s.equals("soapOpera")||s.equals("cartoon")||s.equals("thriller")){ cinema.add(MovieFactory.getMovie(s)); } else { cinema.add(MovieFactory.getMovie(s)); break; } } for(Movie m : cinema){ System.out.println(m.getClass().getSimpleName()); } } static class MovieFactory { static Movie getMovie(String key) { Movie movie = null; // Create a SoapOpera object for the key "soapOpera" if ("soapOpera".equals(key)) { movie = new SoapOpera(); } if ("thriller".equals(key)){ movie = new thriller(); } if ("cartoon".equals(key)){ movie = new cartoon(); } return movie; } } static abstract class Movie { } static class SoapOpera extends Movie { } static class cartoon extends Movie{ } static class thriller extends Movie{ } }

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Karas Backend Developer

2 March 2021, 18:02

All in correct Capitalization. Thanks.

Guadalupe Gagnon

Level 37 , Tampa, United States

2 March 2021, 02:02

There is no condition that says null pointer. It says that "For each valid string entered, you need to display the simple name"

Guadalupe Gagnon

Level 37 , Tampa, United States

2 March 2021, 02:03

solution

Also, the classes are Cartoon and Thriller, not lowercase

Karas Backend Developer

2 March 2021, 18:08

The getMovie method has to be called anyway on the wrong string also, per the requirements. Definitelly will not display anything but requires to be called. there it goes attempt number 102. Thanks.

Guadalupe Gagnon

Level 37 , Tampa, United States

2 March 2021, 18:16

correct, but line 29 should only be reached for each valid entry.