Hello everyone, i have a question about the converter task. I'd like to know if casting the double type like this is another possible way like writing 9/5.0 public static double convertCelsiusToFahrenheit(int celsius) { //write your code here double TF = (double)9/5 * celsius + 32; return TF; I tried to do it but i already submitted the other answer, so i'm curious to know if this would actually work. Thanks