shorty

Question about the task

Resolved

A quick look on whats wrong here ? OUTput is correct except for "each value on a new line" QUESTION: How to guide an array to print elements on a new line? its just randomly happens task to task. lol google solutions " list.forEach(System.out::println); " and " for (String element : list) { System.out.println(element);" doesnt work OR i use them wrong way. wanna fix this(i feel its a small mistake haha) and not using copyOfRange thank you

1. Create an array of 20 numbers.
2. Populate it with values from the keyboard.
3. Create two arrays of 10 numbers each.
4. Copy the large array into the two small ones: half the numbers into the first small array, and the second half into the second small array.
5. Display the second small array, each value on a new line.

Requirements:

The program must create an array of 20 integers.
The program should read 20 numbers from the keyboard for the large array.
The program must create two small arrays of 10 numbers each.
The program must copy one half of the large array into the first small array, copy the second half into the second array, and then display that array on the screen.

package com.codegym.task.task07.task0705; import java.io.BufferedReader; import java.io.InputStreamReader; import java.util.Arrays; /* One large array and two small ones */ public class Solution { public static void main(String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); int[] bigBoy = new int [20]; int n = bigBoy.length; int[] snip = new int[(n / 2)]; int[] shorty = new int[n - snip.length]; for (int i = 0; i < n; i++) { if (i < snip.length) { snip[i] = Integer.parseInt(reader.readLine()); } else { shorty[i - snip.length] = Integer.parseInt(reader.readLine()); } } System.out.println(Arrays.toString(shorty)); } }

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Ioan Toma

Level 22 , Manchester, United Kingdom

16 August 2021, 12:46

solution

Just replace:

System.out.println(Arrays.toString(shorty));

with:

for (String s : shorty) {  //this goes through every one of the array's elements
    System.out.println(s);
}

or:

for (int i = 0; i < array.length; i++) {  //same here
    System.out.println(s);
}

jerry

Level 16 , Earth C-137, Thailand

16 August 2021, 13:04

Thank you! Changed ur code a bit since i didnt use "String s" ✍ for (int i = 0; i < 10; i++) { System.out.println(shorty[i]); it passed the 4th requirement and to pass 3rd 18. int[] snip = new int[(n / 2)]; to [10] 19. int[] shorty = new int[n - snip.length]; to [10]