What number outside the 1-999 range is returning text?

Question about the task

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Final requirement is not met, and I'm stumped as to why.

Enter an integer from the keyboard in the range 1 - 999. Display a string description as follows:
"even single-digit number" - if the number is even and has one digit,
"odd single-digit number" - if the number is odd and has one digit,
"even two-digit number" - if the number is even and has two digits,
"odd two-digit number" - if the number is odd and has two digits,
"even three-digit number" - if the number is even and has three digits,
"odd three-digit number" - if the number is odd and has three digits.
If the entered number does not fall in the range 1 - 999, don't display anything.

Example for 100:
even three-digit number

Example for 51:
odd two-digit number

Requirements:

The program should read one number from the keyboard.
The program should use System.out.println() or System.out.print()..
If the number is even and has one digit, display "even single-digit number".
If the number is odd and has one digit, display "odd single-digit number".
If the number is even and has two digits, display "even two-digit number".
If the number is odd and has two digits, display "odd two-digit number".
If the number is even and has three digits, display "even three-digit number".
If the number is odd and has three digits, display "odd three-digit number".
If the entered number doesn't fall in the range 1 - 999, don't display anything
The program should display a string description of the number and nothing else.

package com.codegym.task.task04.task0427; /* Describing numbers */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(reader.readLine()); int length = (int)(Math.log10(a) + 1); String b = ""; String c = ""; int d = 0; if (a % 2 == 0) b = "even"; if (a % 2 != 0) b = "odd"; if (length == 1) c = " single-digit number"; d = 1; if (length == 2) c = " two-digit number"; d = 1; if (length == 3) c = " three-digit number"; d = 1; if (d == 1 && a > 0) System.out.println(b + c); else System.out.print(""); } }

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Guadalupe Gagnon

Level 37 , Tampa, United States

27 September 2021, 19:25

1000, 1001, 1002. 1003, etc

Greg Martel

Level 5 , Canada

27 September 2021, 19:53

Wouldn't d == 1 be untrue in that case?

Guadalupe Gagnon

Level 37 , Tampa, United States

27 September 2021, 20:00

solution

no. lines 28, 32, and 36 are all reached no matter what. I think you meant to have those lines reached only when the if statements that precede them are true, however you didn't encase them in a block of code to specify this. Java ignores white space so the open/closing brackets are what matters. When no open/closing brackets are present then Java will use ONLY the very next line as part of the statement. Your code functions like this:

if (length == 1){
   c = " single-digit number";
}
d = 1;

if (length == 2){
   c = " two-digit number";
}
d = 1;

if (length == 3){
   c = " three-digit number";
}
d = 1;

Where you should be doing this:

if (length == 1){
   c = " single-digit number";
   d = 1;
}


if (length == 2){
   c = " two-digit number";
   d = 1;
}

if (length == 3){
   c = " three-digit number";
   d = 1;
}

Greg Martel

Level 5 , Canada

27 September 2021, 20:02

Ohhh! Thanks a thousand!