Not able to pass the last condition not sure why please give me hint

Question about the task

Creating a two-dimensional array

Java Syntax, Level 6, Lesson 6

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Not able to pass the last condition not sure why please provide me suggestion

A two-dimensional array is an array of arrays. That is, an array where each cell holds a reference to an array.
But it is much easier to think of it as a table that has a number of rows (first dimension) and a number of columns (second dimension).
In this task, we will create such an array.

Implement the main(String[]) method, which:

Reads from the console a number R — the number of rows in the array. The number must be greater than 0.
Then it reads R numbers from the console (any numbers greater than 0).
Then it initializes the two-dimensional multiArray array using:
- the number of rows R;
- row arrays whose size corresponds to the numbers entered in step 2 (in the order they are entered).

Example:

The number 5 is entered.
The numbers 1, 7, 5, 9, and 3 are entered.
And we get an array like this:
[] [][][][][][][] [][][][][] [][][][][][][][][] [][][]

Requirements:

The Solution class should have an uninitialized public static int[][] multiArray variable.
The main(String[]) method must read N+1 numbers from the keyboard.
In the main(String[]) method, initialize and fill the two-dimensional array as outlined in the task conditions.

package en.codegym.task.pro.task05.task0511; import java.util.Scanner; /* Creating a two-dimensional array */ public class Solution { public static int[][] multiArray; public static void main(String[] args) { //write your code here Scanner s= new Scanner(System.in); // multiArray [0] = new int[1]; // multiArray [1] = new int [2]; int R= s.nextInt(); int count=0; if(R>0){ while(s.hasNextInt()){ int col= s.nextInt(); multiArray = new int [R][col]; for(int i=R; i<=R;i++){ for(int j=0; j<col;j++){ System.out.print("[]"); } System.out.println(""); } } } } }

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Guadalupe Gagnon

Level 37 , Tampa, United States

10 March 2022, 18:01

#1 The first number entered, R, should be the amount of subsequent numbers read in. This does not occur in the above code and the loop at line 23 reads infinitely. For example, if I entered 5 as the first number for R then I would expect 5 and only 5 subsequent numbers read. This will need to be fixed #2 Line 25 reinitializes mutliArray each loop cycle to a length of R and a width of col. This will not reach the intended result of having each sub array be of varrying lengths (also known as a jagged array). For example, if I entered 5 for R and then 1 for the first number thereafter, multiArray would look like this: [0] [0] [0] [0] [0] if I then entered 7 multiArray would look like this: [0, 0, 0, 0, 0, 0, 0] [0, 0, 0, 0, 0, 0, 0] [0, 0, 0, 0, 0, 0, 0] [0, 0, 0, 0, 0, 0, 0] [0, 0, 0, 0, 0, 0, 0] and so on. In effect the length and width of multiArray when the algorithm ends would be R and the last value entered in the loop. In the example given in the task the end result would be that multiArray would have a length of 5 and width of 3: [0, 0, 0] [0, 0, 0] [0, 0, 0] [0, 0, 0] [0, 0, 0] instead of a length of 5 and subsequent widths of 1, 7, 5, 9, and 3: [0] [0, 0, 0, 0, 0, 0, 0] [0, 0, 0, 0, 0] [0, 0, 0, 0, 0, 0, 0,0 ,0] [0, 0, 0] A couple of other concerns: Line 21 does not have a purpose. I would remove it. The code should not output anything. Line 26 to 34 may, or may not, be causing validation failure. Even if they are not, they are unnecessary and should be removed.