error : line 19 : 'else' without 'if' , Please help me to resolve this error... !!!

Question about the task

Under discussion

package com.codegym.task.task04.task0409;

/*
Closest to 10

*/

public class Solution {
    public static void main(String[] args) {
        displayClosestToTen(8, 11);
        displayClosestToTen(7, 14);
    }

    public static void displayClosestToTen(int a, int b) {
        int num1 = abs(10 - a);
        int num2 = abs(10 - b);
        if(num1 < num2);
            System.out.println(a + " is closest to ten");
        else if(num1 > num2)
            System.out.println(b+ " is closest to ten");
        else
            System.out.println(b+ " is closest to ten");



    }

    public static int abs(int a) {
        if (a < 0) {
            return -a;
        } else {
            return a;
        }
    }
}

Write the displayClosestToTen method. The method should display the argument that is nearest to 10.
For example, given the numbers 8 and 11, 11 is closest to ten. If both numbers are equally close to 10, then display either of them.

Hint:
use the public static int abs(int a) method, which returns the absolute value of a number.

Requirements:

The program should display text on the screen.
The main method should not call System.out.println or System.out.print().
The main method should call the displayClosestToTen method.
The displayClosestToTen method should call the abs method.
The displayClosestToTen method should display a number on the screen in accordance with the task conditions.

package com.codegym.task.task04.task0409; /* Closest to 10 */ public class Solution { public static void main(String[] args) { displayClosestToTen(8, 11); displayClosestToTen(7, 14); } public static void displayClosestToTen(int a, int b) { int num1 = abs(10 - a); int num2 = abs(10 - b); if (num1 < num2); System.out.println(a + " is closest to ten"); else if(num1 > num2) System.out.println(b+ " is closest to ten"); else System.out.println(b+ " is closest to ten"); } public static int abs(int a) { if (a < 0) { return -a; } else { return a; } } }

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novik90

Level 16 , Saint Petersburg, Russian Federation

3 February 2019, 11:48

the third “if” is superfluous try

if (num1 < num2) {
            System.out.println(a + " is closest to ten");
} else {
            System.out.println(b + " is closest to ten");
}

and use debugger

kapil

Level 12 , delhi, India

2 February 2019, 16:41

try...by removing ; after if at line 17

Guadalupe Gagnon

Level 37 , Tampa, United States

4 February 2019, 14:45

Along with what kapil points out on line 17, the text you are outputting will fail the task. It should only output the number closest to ten without " is closest to ten".