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public static void main(String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(reader.readLine()); if (a <0 && a%2==0){ System.out.println("Negative even number"); } else if (a<0 && a%2!=0){ System.out.println("Negative odd number"); } else if (a == 0){ System.out.println("Zero"); } else if (a>0 && a%2==0){ System.out.println("Positive even number"); } else if (a>0 && a%2!=0){ System.out.println("Positive odd number"); } } }

BufferedReader scan=new BufferedReader(new InputStreamReader(System.in)); int a=Integer.parseInt(scan.readLine()); if((a<0)&&(a%2==0)) System.out.println("Negative even number"); else if ((a<0)&&(a%2!=0)) System.out.println("Negative odd number"); else if (a==0) System.out.println("Zero"); else if ((a>0)&&(a%2==0)) System.out.println("Positive even number"); else if ((a>0)&&(a%2!=0)) System.out.println("Positive odd number");

if(a == 0) System.out.println("Zero"); else if(a < 0) { System.out.println("Negative "); if(a % 2 == 0) System.out.println("even number "); else System.out.println("odd number "); } else if(a > 0) { System.out.println("Positive "); if(a % 2 == 0) System.out.println("even number "); else System.out.println("odd number "); }

As the topics is on Boolean i have solved it boolean way. BufferedReader r = new BufferedReader(new InputStreamReader(System.in)); String s = r.readLine(); int a = Integer.parseInt(s); boolean m= isPositive(a); boolean n= isDivisiblebytwo(a); if (a==0) System.out.println("Zero"); else if (m && n) System.out.println("Positive even number"); else if (m && !n) System.out.println("Positive odd number"); else if (!m && n) System.out.println("Negative even number"); else if (!m && !n) System.out.println("Negative odd number"); } static boolean isPositive (int x) { if (x>0) return true; else return false; } static boolean isDivisiblebytwo(int y) { if (y%2==0) return true; else return false; }

Was getting the same error msg using different methods but managed to resolve it after following the sequence of code "Negative even number" - if the number is negative and even, "Negative odd number" - if the number is negative and odd, if(a<0) { if(a%2==0) System.out.println("Negative even number"); else System.out.println("Negative odd number");

Hi Harinath, I noticed the server side (the validator) is picky with the code style and even with the order of instructions or console input. My code wouldn't differ much from yours. Instead of ==1 I used a broader negation, !=0. For we may have situations when asked to make a dictionary with pairs of numbers who divide with remainder zero and the divisor won't be a fix number. Also line 28 seems to have a redundant "if" condition. Due to the fact that you already exhausted all possibilities but "==0" up to that point, just "else" may be suffice. Let me know how it goes.

Using a nested if else statement will make it more simpler, if(a>0){ if(a%2==0) { +ve even } else { +ve odd } } if(a<0){ if(a%2==0) { -ve even } else { -ve odd } }

Put this at line 12:

System.out.println("Using a negative odd number, -9, the result of:  -9 % 2 = " + (-9%2));

and run it. This should give you a good idea of what the problem is. Once you locate it, make sure to delete that line or it will cause a verification fail.

else if(a > 0) {

else if(a < 0) {