How did you do it?

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I got the answer but I'm really curious how others went about the solution. I'm sure there are better/more succinct ways to solve this task. Specifically, how did you handle "12."? My crazy solution involves splitting each line into words. If the first character of a word is a number, then I split the word into characters. Then I write sequential numbers into a prefix string and any characters following the last sequential digit into a suffix string.

if (Character.isDigit(firstChar)) {
    char[] characters = word.toCharArray();
    String prefix = "";
    String suffix = "";

    for (int j = 0; j < characters.length; j++) {
        if (Character.isDigit(characters[j])) {
            prefix += characters[j];
        } else {
            suffix += characters[j];
        }
    }
    int num = Integer.parseInt(prefix);
    //search map for number...
}
//other stuff

Phew, that's a lot of work! There have to be better solutions out there!

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Nyerges Ferenc

Level 29 , Bükkábrány, Hungary

20 November 2020, 21:43

Many thanks, the concept worked for me as well :-)

Guadalupe Gagnon

Level 37 , Tampa, United States

28 February 2019, 22:21

private static void correctPrintln(String line) {
        String[] words = line.split(" "); // splits line
        StringBuilder sb = new StringBuilder();
        for(int i = 0; i < words.length;i++) {
            String x1 = words[i].replaceAll("[a-zA-Z0-9]",""); // stores punctuation
            words[i] = words[i].replaceAll("[^a-zA-Z0-9]",""); // removes punctuation
            try { // tries to parse into a number, if failed just ignores.
                int x = Integer.parseInt(words[i]);
                if (x >= 0 && x <= 12)
                    words[i] = map.get(x);
            }catch (Exception ignored) { }
            sb.append(words[i] + x1 +" "); // creates output string
        }
        System.out.println(sb.toString().trim()); // outputs and removes last space
}

This is what I did. I don't know if it is better or not. In the main method I used a buffered reader and passed each line I read into this method where all the work is done.

Andrew

Level 29 , Seattle, United States

1 March 2019, 17:54

solution

I thought about using the try {parseint} thing too. Thanks for sharing!