Sum of the digits of a three-digit number

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package com.codegym.task.task01.task0132;

/*
Sum of the digits of a three-digit number

*/

public class Solution {
    public static void main(String[] args) {
        System.out.println(sumDigitsInNumber(546));
    }

    public static int sumDigitsInNumber(int number) {
        int a = 5;
        int b = 4;
        int c = 6;
        int d = number%10;
        int e = d + number;
            return number / 10;

        }

}

i do not understand no logic ..

Write the code for sumDigitsInNumber(int number). The method takes a three-digit whole number. You need to calculate the sum of the digits of this number, and then return the result.

Consider this example:
The sumDigitsInNumber method is called with the argument 546.

Example output:
15

Requirements:

The program must not read data from the keyboard.
The sumDigitsInNumber(int) method must be public and static.
The sumDigitsInNumber method must return an int.
The sumDigitsInNumber method should not display anything.
The sumDigitsInNumber method must return the sum of all digits in the parameter number.

package com.codegym.task.task01.task0132; /* Sum of the digits of a three-digit number */ public class Solution { public static void main(String[] args) { System.out.println(sumDigitsInNumber(546)); } public static int sumDigitsInNumber(int number) { int a = 5; int b = 4; int c = 6; int d = number%10; int e = d + number; return number / 10; } }

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Lukaluk

Level 8 , Świętochłowice, Poland

15 May 2019, 10:23

you can also try this formula... a = (number/100); (for integer numbers) result will be WHOLE ... b = (number - a*100)/10; (for integer numbers) result will be WHOLE ... c = (number - a*100 - b*10); (for integer numbers) result will be WHOLE ... add digits

June Anthony

Level 4 , Parañaque, Philippines

8 April 2019, 04:03

divide the number by 10. get the remainder. thats the first digit. divide the number by 10. divide the answer by 10 get the remainder. thats the 2nd digit. divide the number by 100, thats the 3rs digit. add all the digits

Andrew

Level 29 , Seattle, United States

3 April 2019, 16:48

useful

Your code is ignoring variables a - e and only returning the number parameter / 10, so in this case, 54. You need to create a solution that will work regardless of the 3 digit number entered. Hints: "% 10" gets the last digit of a number (rightmost digit) - for "546" this gets you "6". "/ 10" gets the number excluding the last digit - for "546" this gets you "54". You need to create some kind of program that cycles through all the digits of the number and sums each of the 3 digits together. Consider using a loop if you have covered that by this point in the course.