I cant seem to find out the error

Question about the task

Under discussion

public static void main(String[] args) throws Exception {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        String syr = reader.readLine();
        int nyr = Integer.parseInt(syr);

        if( (nyr%4 == 0) && (nyr% 100 != 0))
        {
            System.out.println("Number of days in a year: 366.");
        }
        else if((nyr%100 == 0) && (nyr% 400 == 0)) {
            System.out.println("Number of days in a year: 366.");
        }


        else{
           System.out.println("Number of days in a year: 365.");
       }
}

Use the keyboard to enter a year, and then determine the number of days in the year. Display the result as follows:
Number of days in the year: x
, where
x is 366 for a leap year, and
x is 365 for an ordinary year.

Hint:
A leap year is 366 days, but an ordinary year is 365 days.
1) if the year is evenly divisible by 400, then it is a leap year;
2) for other years, if the year is evenly divisible by 100, then it is a regular year;
3) for other years, if the year is evenly divisible by 4, then it is a leap year;
4) all remaining years are not leap years.
Thus, the years 1700, 1800, and 1900 are not leap years, since they are multiples of 100 but not 400.
The years 1600 and 2000 are leap years, since they are multiples of 100 and multiples of 400.
The years 2100, 2200 and 2300 are not leap years.

Requirements:

The program should read a number from the keyboard.
The program should display text on the screen according to the task conditions.
If the entered year is a leap year, you should display: "Number of days in the year: 366".
If the entered year is not a leap year, you should display: "Number of days in the year: 365".

package com.codegym.task.task04.task0414; /* Number of days in a year */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); String syr = reader.readLine(); int nyr = Integer.parseInt(syr); if( (nyr%4 == 0) && (nyr% 100 != 0)) { System.out.println("Number of days in a year: 366."); } else if((nyr%100 == 0) && (nyr% 400 == 0)) { System.out.println("Number of days in a year: 366."); } else{ System.out.println("Number of days in a year: 365."); } } }

Comments (3)

Popular
New
Old

You must be signed in to leave a comment

Vijay Rangan

Level 5 , Jakarta, India

29 October 2018, 08:10

u need to use nested loop (create if else loop inside another if loop) first check if the year div by 4 if yes enter into the loop else "not leap year" second check if the year div by 100 if no " leap year " else go into the loop in third loop check if year div by 400 if yes (leap year) else (No)

Niranjan Soni

Level 15 , Bangalore, India

23 September 2018, 11:52

you have to add 1 more case. else if(nyr%100 == 0 && nyr%400 != 0){ System.out.println("Number of days in the year: "+"365"); } and remove remove periods from the print statements.

Level 41

29 August 2018, 08:34

Delete the point at the end of the output