Where is the error?

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package com.codegym.task.task04.task0426; /* Labels and numbers */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here BufferedReader r = new BufferedReader (new InputStreamReader(System.in)); String s = r.readLine(); int T = Integer.parseInt(s); if((T > 0) && (T%2 == 0)){ System.out.println("Positive even number"); } else if ((T>0) && (T%2 == 1)){ System.out.println("Positive odd number"); } if ( T == 0){ System.out.println("Zero"); } else if ((T<0) && T%1 == 0){ System.out.println("Negative even number"); } else { System.out.println("Negative odd number"); } } }

Use the keyboard to enter an integer. Display a string description as follows:
"Negative even number" - if the number is negative and even,
"Negative odd number" - if the number is negative and odd,
"Zero" - if the number is 0,
"Positive even number" - if the number is positive and even,
"Positive odd number" - if the number is positive and odd.

Example for 100:
Positive even number

Example for -51:
Negative odd number

Requirements:

The program should read a number from the keyboard.
The program should use System.out.println() or System.out.print().
If the number is negative and even, display "Negative even number".
If the number is negative and odd, display "Negative odd number".
If the number is 0, display "Zero".
If the number is positive and even, display "Positive even number".
If the number is positive and odd, display "Positive odd number".

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Кайрат Борбиев

Level 7 , Bishkek, Kyrgyzstan

8 July 2019, 12:36

if(t > 0){ if(t % 2 == 0){ System.out.println("Positive even number"); } else { System.out.println("Positive odd number"); } }else.... then you decide =)

ulmas9025

Level 20 , Tashkent, Uzbekistan

19 April 2019, 04:42

if(n<0 && n % 2 == 0){ System.out.println ("Negative even number"); }else if(n < 0 && n % 2 != 0 ){ System.out.println ("Negative odd number"); }else if ( n == 0 ){ System.out.println ("Zero"); }else if ( n > 0 && n % 2 == 0 ){ System.out.println ("Positive even number"); }else if ( n > 0 && n % 2 != 0 ){ System.out.println ("Positive odd number" ); }

Ops guy

Level 17 , Round Rock, TX, United States

18 April 2019, 20:09

this is incorrect but it is close :)

if ( T == 0){
    System.out.println("Zero");
}

else if ((T<0) && T%1 == 0){
    System.out.println("Negative even number");
}

Guadalupe Gagnon

Level 37 , Tampa, United States

18 April 2019, 13:18

You have two separate if else structures, the first between lines 19-24 and the second between lines 26-37. The second structure has the default output of "Negative odd number" (default meaning that it will be run in the case that the other 'if' conditions are not met). So if you enter any positive number the code will have the output: Positive <EvenOdd> number Negative odd number You need to fix this.