I'm a little unsure about what it's asking.

Question about the task

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When it says to make sure that the getDescription method doesn't return any null strings, I went to make a while loop that broke once there was an input such as this. public static class Idea{ public String getDescription() throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String anything = br.readLine(); while(true) if (anything.equals(null)) System.out.println("Give me an Idea"); else{ break; } return anything; } } But it replied that the statement, (anything.equals(null)) would always be false. So now I'm confused as to why it isn't being verified. Am I just overthinking this right now? I feel like I am. EDIT: I was just overthinking it.

1. In the Solution class, create the public static Idea class
2. In the Idea class, declare a public String getDescription() method that returns any non-empty string
3. In the Solution class, create a static public void printIdea(Idea idea) method that will display a description of the idea (what the getDescription method returns)

Requirements:

In the Solution class, create the public static Idea class.
In the Idea class, create the public String getDescription() method.
The getDescription method must return any non-empty string.
In the Solution class, create a public static void printIdea(Idea idea) method.
The printIdea method should display the idea description on the screen.

package com.codegym.task.task06.task0617; /* Notepad for new ideas 1. In the Solution class, create the public static Idea class 2. In the Idea class, declare a public String getDescription() method that returns any non-empty string 3. In the Solution class, create a static public void printIdea(Idea idea) method that will display a description of the idea (what the getDescription method returns) Requirements: 1. In the Solution class, create the public static Idea class. 2. In the Idea class, create the public String getDescription() method. 3. The getDescription method must return any non-empty string. 4. In the Solution class, create a public static void printIdea(Idea idea) method. 5. The printIdea method should display the idea description on the screen. */ import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.Scanner; public class Solution { public static class Idea{ public String getDescription() throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String anything = br.readLine(); return anything; } } public static void printIdea(Idea idea) throws IOException{ System.out.println(idea.getDescription()); } public static void main(String[] args) throws IOException { printIdea(new Idea()); } //write your code here }

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Heroboy Blue

Level 10

12 December 2019, 03:10

Hi,Bro...This is my Solution.

package zh.codegym.task.task06.task0617;

/*
Notepad for new ideas

*/

public class Solution {
    public static void main(String[] args) {
        printIdea(new Idea());
    }

    //write your code here
    public static class Idea{
        public static String str = "str";
        public String getDescription(){
            return str;
        }
    }

    public static void printIdea(Idea idea){
        System.out.println(idea.getDescription());
    }
}

Guadalupe Gagnon

Level 37 , Tampa, United States

2 May 2019, 01:38

I don't know what you did to solve this, but for future reference: When you want to check the actual data contained in a string, use the equals method like: *stringVariable*.equals(*testStringOrVariable*). When you want to test if it is null or not, use the equality check denoted by a double equals sign '==', so: *stringVariable* == null

Guadalupe Gagnon

Level 37 , Tampa, United States

2 May 2019, 01:58

Take this bit of code for example:

public class Solution {
    public static void main(String[] args) throws IOException {
        String test1 = "test1", test11 = test1, test2 = new String("test1");
        System.out.println("test1.equals(test11)? " + test1.equals(test11));
        System.out.println("test1.equals(test2)? " + test1.equals(test2));
        System.out.println("test11.equals(test2)? " + test11.equals(test2));
        System.out.println();
        System.out.println("test1 == test11? " + (test1 == test11));
        System.out.println("test1 == test2? " + (test1 == test2));
        System.out.println("test11 == test2? " + (test11 == test2));
    }
}

the value of all the string variables is "test1", however when you run the code the output is: test1.equals(test11)? true test1.equals(test2)? true test11.equals(test2)? true test1 == test11? true test1 == test2? false test11 == test2? false That is because, as i mentioned above, the equals method checks the actual data stored in the variable, while the equality operator checks if the objects point to the same place in memory. If I changed the test 2 variable from new String("test1") to just plain "test1", the code would all return all true. This is because the way that strings are stroed in memory and is a bit of an advanced topic. I don't want to confuse you too much, and I don't even fully understand it all myself. You can read a little here if interested: https://stackoverflow.com/questions/513832/how-do-i-compare-strings-in-java

Connor

Level 8 , Boston, United States

2 May 2019, 02:44

Lol, I took out the whole keyboard input method and just put return ""; I reread the requirements and saw that the keyboard didn't need to input any data and realized I really was overthinking it. Also, appreciate the link very informative article.