I can not verify, made a dozen options, does not work

Question about the task

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// import java.security.acl.LastOwnerException; import java.util.HashMap; import java.util.HashSet; import java.util.Map; /* Перепись населения */ public class Solution { public static HashMap<String, String> createMap() { HashMap <String, String> map = new HashMap <> ( ); map.hashCode (); map.put ("Ivanov","Vasya"); map.put ("Vasilev","Vasya"); map.put ("Konstantinov","Vasya"); map.put ("IvanovVasilev", "Ivan"); map.put ("IvanovKonstantinov", "Kolya"); map.put ("Kolkin", "Kolya"); map.put ("IvanovTemkin", "Tema"); map.put ("IvanovIvanov", "Maks"); map.put ("Temkin", "Tema"); map.put ("IvanovIvanovIvanov", "Petya"); for (String key: map.keySet ()) { // System.out.println (key); } return map; } public static int getCountTheSameFirstName(HashMap<String, String> map, String name) { int count = 0; for (Map.Entry <String,String> korzina: map.entrySet ()){ if (korzina.getValue ().equals ( name )) count++; // System.out.println(name + " - " + count); } // System.out.println ("How many name: " + name + " " + count); return count; } public static int getCountTheSameLastName(HashMap<String, String> map, String lastName) { int yes = map.containsKey ( lastName ) ? 1:0; // System.out.println ("Есть ли такая фамилия: " + yes); return yes; } public static void main(String[] args) { HashMap <String, String> map = createMap (); getCountTheSameFirstName (map,"Maks"); getCountTheSameLastName ( map, "Ivanov3" ); } }

Create a Map<String, String> and add ten entries that represent (last name, first name) pairs.
Check how many people have the same first name or last name.

Requirements:

The program should not display text on the screen.
The program should not read values from the keyboard.
The createMap() method must create and return a HashMap that has (String, String) elements and contains 10 entries that represent (last name, first name) pairs.
The getSameFirstNameCount() method must return the number of people whose first name is the same as the name parameter.
The getSameLastNameCount() method must return the number of people whose last name is the same as the lastName parameter.

package com.javarush.task.task08.task0815; import java.util.HashMap; import java.util.HashSet; /* Перепись населения */ public class Solution { public static HashMap<String, String> createMap() { HashMap<String, String> Map = new HashMap<String, String>(); Map.put("kekSurname3", "kekName1"); Map.put("kekSurname2", "kekName3"); Map.put("kekSurnamfe3", "kekName3"); Map.put("kekSurdname", "kekName"); Map.put("kekSusrname5", "kekName5"); Map.put("kekSuvrname", "kekName"); Map.put("kekSucrname", "kekName"); Map.put("kekSudrname8", "kekName8"); Map.put("keksSurname", "kekName"); Map.put("kehkSurname", "kekName"); return Map; } public static int getCountTheSameFirstName(HashMap<String, String> map, String name) { int i = 0; for(String n : map.values()) if(n.equals(name)) i++; return i; } public static int getCountTheSameLastName(HashMap<String, String> map, String lastName) { int i = 0; for(String n : map.keySet()) if(n.equals(lastName)) i++; return i; } public static void main(String[] args) { } }

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Ahmed

Level 23 , Amsterdam, Netherlands

10 May 2019, 22:17

solution

You code i correct. You only need to change the name of the methodes: 1- getSameFirstNameCount 2- getSameLastNameCount

Sergei Polakov

Level 11 , Donets'k, Ukraine

11 May 2019, 11:03

thanks brother! I knew that this is where the glitch, I just never saw it!

Ahmed

Level 23 , Amsterdam, Netherlands

11 May 2019, 12:24

You're welcome!

Roman

Level 41

10 May 2019, 10:01

Read the requirements that are not passed very carefully!

Alex Vypirailenko Java Developer at Toshiba Global Comme

8 May 2019, 12:16

For the getCountTheSameFirstName() method I suggest you read about the Collections class and its frequency() method. For the getCountTheSameLastName() method you can just use the containskey() method from the HashMap class.

Sergei Polakov

Level 11 , Donets'k, Ukraine

8 May 2019, 13:02

thanks, I read everything .. there are a few business options, I think correctly, but not verifierade unfortunately.. I would just like to take a look at the code that is verified

Alex Vypirailenko Java Developer at Toshiba Global Comme

9 May 2019, 07:07

Unfortunately, we can not provide verifiable code. You will need to solve the task yourself.

Sergei Polakov

Level 11 , Donets'k, Ukraine

9 May 2019, 07:32

import java.util.HashMap; import java.util.HashSet; import java.util.Map; /* Перепись населения */ public class Solution { public static HashMap<String, String> createMap() { HashMap <String, String> map = new HashMap <> ( ); map.hashCode (); map.put ("Ivanov","Vasya"); map.put ("Vasilev","Vasya"); map.put ("Konstantinov","Vasya"); map.put ("IvanovVasilev", "Ivan"); map.put ("IvanovKonstantinov", "Kolya"); map.put ("Kolkin", "Kolya"); map.put ("IvanovTemkin", "Tema"); map.put ("IvanovIvanov", "Maks"); map.put ("Temkin", "Tema"); map.put ("IvanovIvanovIvanov", "Petya"); for (String key: map.keySet ()) { // System.out.println (key); } return map; } public static int getCountTheSameFirstName(HashMap<String, String> map, String name) { int count = 0; for (Map.Entry <String,String> korzina: map.entrySet ()){ if (korzina.getValue ().equals ( name )) count++; // System.out.println(name + " - " + count); } // System.out.println ("How many name: " + name + " " + count); return count; } public static int getCountTheSameLastName(HashMap<String, String> map, String lastName) { int yes = map.containsKey ( lastName ) ? 1:0; // System.out.println ("Есть ли такая фамилия: " + yes); return yes; } public static void main(String[] args) { // HashMap <String, String> map = createMap (); // getCountTheSameFirstName (map,"Maks"); // getCountTheSameLastName ( map, "Ivanov3" ); } } ================== what could be a mistake?

Sergei Polakov

Level 11 , Donets'k, Ukraine

9 May 2019, 07:34

despite the fact that doing the next task, by analogy.. and all verified without problems