How to fix the error?

Question about the task

Even and odd digits

Java Syntax, Level 6, Lesson 5

Under discussion

package com.codegym.task.task06.task0606;

import java.io.*;
import java.util.Scanner;

public class Solution {

    public static int even;
    public static int odd;

    public static void main(String[] args)throws Exception {

        Scanner in=new Scanner(System.in);
        int number = in.nextInt();

        if (number < 0) number *= -1;

        while( number > 1 ){
            if (number %2 == 0)  {
                even++;
                number /= 10;
            }
            else{
                odd++;
                number /= 10;
            }
        }
            System.out.println("Even: "+even+"Odd: "+odd);
    }
}

error

The displayed text must match the task conditions.

Use the keyboard to enter a positive number. Determine the number of even digits and odd digits in the entered number.
If a number is divisible by 2 without a remainder (i.e. the remainder is zero), then it is even.
And we'll increase the even digit counter (static variable even) by 1.
Otherwise, the number is odd, so we'll increase the odd digit counter (static variable odd).
Display the following message: "Even: a Odd: b", where a is the number of even digits and b is the number of odd digits.

Example for 4445:
Even: 3 Odd: 1

Requirements:

The program must read data from the keyboard.
The main method should calculate how many even digits are in the entered number and then write this number to the variable even.
The main method should calculate how many odd digits are in the entered number and then write this number to the variable odd.
The program should display text on the screen.
The displayed text must match the task conditions.

package com.codegym.task.task06.task0606; import java.io.*; import java.util.Scanner; public class Solution { public static int even; public static int odd; public static void main(String[] args)throws Exception { Scanner in=new Scanner(System.in); int number = in.nextInt(); if (number < 0) number *= -1; while( number > 1 ){ if (number %2 == 0) { even++; number /= 10; } else{ odd++; number /= 10; } } System.out.println("Even: "+even+"Odd: "+odd); } }

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Hoang Khai

Level 8 , Chantilly, United States

11 July 2019, 02:08

import java.util.Scanner; public class Solution { public static int even; public static int odd; public static void main(String[] args) throws IOException { Scanner s=new Scanner(System.in); int a=s.nextInt(); while (a>0){ int c=a; c%=10; if (c%2==0) even+=1; else odd+=1; a/=10; } System.out.println("Even:"+" "+even+" " +"Odd:"+" "+odd); } }

Vineet Yadav

Level 16 , Mumbai, India

23 May 2019, 10:10

public class Solution {

    public static int even;
    public static int odd;

    public static void main(String[] args) throws IOException {
        //write your code here
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        int n = Integer.parseInt(reader.readLine());
        while(n!=0){
            if(n%2 == 0){
                even++;
            }else{
                odd++;
            }
            n = n/10;
        }
        System.out.println("Even:" + " " + even + " Odd:" + " " + odd);
    }
}

Clark

Level 17 , Berlin, Germany

18 May 2019, 19:19

Check your while Condition; you should proof the number length not the number himself. What is happens, if the number at least really 1 (example: you have the int 12, so you check in the first loop 2 = even; in the next loop the number ist 1 and the while loop stops).

thinhnguyen

Level 24 , Danang, Viet Nam

18 May 2019, 10:07

you forgot a space before odd

ThomasLC

Level 16 , Singapore, Singapore

18 May 2019, 10:01

Check your output carefully; System.out.println("Even: "+even+"Odd: "+odd); This will output: "Even: 3Odd: 1" you need it to output "Even: 3 Odd: 1" Hope that helps :)

Serg

Level 23 , Tyumen, Russian

18 May 2019, 11:22

corrected

System.out.println("Even: " + even + " Odd: "+odd);

Did not help. Same mistake