Please share what else needs to be changed in the following code

Question about the task

Three numbers

Java Syntax, Level 4, Lesson 6

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Please share what else needs to be changed in the following code:

Use the keyboard to enter three integers. One of the numbers is unique. The other two are identical. Display the ordinal number of the number that is different from the others.

Example for 4 6 6:
1

Example for 6 6 3:
3

Requirements:

The program should read the numbers from the keyboard.
The program should use System.out.println() or System.out.print().
The program should display the ordinal number of the number that is different from the others.
If all the numbers are different, don't display anything.

package com.codegym.task.task04.task0424; /* Three numbers */ import java.io.*; import java.util.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here Scanner sc = new Scanner(System.in); int n1 = sc.nextInt(); int n2 = sc.nextInt(); int n3 = sc.nextInt(); int [] arrn = {n1,n2,n3}; if (arrn[0] == arrn[1]) { System.out.println(2); } else if (arrn[0]== arrn[2]) { System.out.println(1); } else if (arrn[1]== arrn[2]) { System.out.println(0); } else {} } }

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Sreekant

Level 10 , Anaheim, United States

19 January 2020, 20:07

you are only comparing the 2 numbers. what if all 3 numbers are same? your code display 1 which is wrong

Aman saw

Level 9 , Madanpur, India

9 June 2019, 18:55

perform this simple code:- package com.codegym.task.task04.task0424; /* Three numbers */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(br.readLine()); int b = Integer.parseInt(br.readLine()); int c = Integer.parseInt(br.readLine()); if(a==b){ System.out.println("3"); } else if(b==c){ System.out.println("1"); } else if(a==c){ System.out.println("2"); } } }

ThomasLC

Level 16 , Singapore, Singapore

20 May 2019, 15:23

useful

Read the conditions carefully; in their example output [ 4 6 6 ], the different number, which is 4, the output is its position, which is the first position, or "1" You are printing out 0,1,2

Sudhansu Shekhar

Level 6 , Jaipur, India

22 May 2019, 05:31

I'm getting following error while verifying: error @ : "If all the numbers are different, don't display anything. " Please help.

Sudhansu Shekhar

Level 6 , Jaipur, India

22 May 2019, 05:39

package com.codegym.task.task04.task0424;

/*
Three numbers

*/

import java.io.*;
import java.util.*;

public class Solution {
    public static void main(String[] args) throws Exception {
        //write your code here
        Scanner sc = new Scanner(System.in);


			int n1 = sc.nextInt();
		    int n2 = sc.nextInt();
		    int n3 = sc.nextInt();

		    int [] arrn = {n1,n2,n3};

		    if ( arrn[0] != arrn[1] && arrn[1] != arrn[2] && arrn[0] != arrn[1])
		    {
		        //System.out.println("Nothing Equalls.");
		    }
		    else  if ( (arrn[0] != arrn[1]) && (arrn[0] != arrn[2]))
		    {
		    	System.out.println("1");
		    }
		    else if ((arrn[1] != arrn[2]) && (arrn[1] != arrn[0]) )
		    {
		    	System.out.println("2");
		    }
		    else if ((arrn[2] != arrn[1]) && (arrn[2] != arrn[0]) )
		    {
		    	System.out.println("3");
		    }
		    else {}
	}

	}


On executing above code web verification says that code should print the index no. of no. different then others.

ThomasLC

Level 16 , Singapore, Singapore

22 May 2019, 08:20

The condition states don't display anything, not display a message on the console saying "nothing equals". Simply remove that part of your algorithm so the method does nothing if all is different. Remove: if ( arrn[0] != arrn[1] && arrn[1] != arrn[2] && arrn[0] != arrn[1]) { //System.out.println("Nothing Equalls."); } (Of course fix the flow of the rest of the algorithm too once this is removed)