Can someone explain what might be wrong with the code? This particular section:

Question about the task

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for (String line : arrOfStr) {
            if (line.contains("=")) {
                try {
                    double d = Double.parseDouble(line.substring(line.indexOf('=') + 1));
                    if (d % 1 == 0)
                        break;
                    alert(d);
                    break;
                } catch (NumberFormatException e) {
                    String str = line.substring(line.indexOf('=') + 1);
                    alert(str);
                    break;
                }
            }
        }

Read a URL from the console.
Display a space-delimited list of all the parameters (The parameters follow the "?" and are separated by "&", e.g. "lvl=15").
The URL contains at least 1 parameter.
The parameters must be displayed in the same order in which they are present in the URL.
If the obj parameter is present, pass its value to the relevant alert method.
alert(double value) - for numbers (fractional numbers have a decimal point)
alert(String value) - for strings
Note that the alert method must be called AFTER the list of all parameters is displayed.

Example 1

Input:
http://codegym.cc/alpha/index.html?lvl=15&view&name=Amigo

Output:
lvl view name

Example 2

Input:
http://codegym.cc/alpha/index.html?obj=3.14&name=Amigo

Output:
obj name double: 3.14

Requirements:

The program should read only one line from the keyboard.
The Solution class must not have static fields.
The program must display data on the screen in accordance with the task conditions.
The program should call the alert method with the double parameter if the obj parameter can be correctly converted to a double.
The program should call the alert method with the String parameter if the obj parameter CANNOT be correctly converted to a double.

package com.codegym.task.task15.task1527; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.ArrayList; import java.util.List; /* Request parser */ public class Solution { public static void main(String[] args) throws IOException { //write your code here BufferedReader rd = new BufferedReader(new InputStreamReader(System.in)); String URL = rd.readLine(); String[] arrOfStr = URL.split("[?&]"); List<String> paramList = new ArrayList<>(); for (String line : arrOfStr) { if (line.contains("=")) paramList.add(line.substring(0, line.indexOf('='))); if (!line.contains("http://") && !line.contains("=")) paramList.add(line); } for (String param : paramList) System.out.print(param + " "); System.out.println(); for (String line : arrOfStr) { if (line.contains("=")) { try { double d = Double.parseDouble(line.substring(line.indexOf('=') + 1)); if (d % 1 == 0) break; alert(d); break; } catch (NumberFormatException e) { String str = line.substring(line.indexOf('=') + 1); alert(str); break; } } } } public static void alert(double value) { System.out.println("double: " + value); } public static void alert(String value) { System.out.println("String: " + value); } } // http://codegym.cc/alpha/index.html?obj=3.14&name=Amigo

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Raivo Lapiņš

Level 18 , Riga, Latvia

28 May 2019, 14:34

solution

Try this if (d % 1 == 0 && !line.contains("obj")) instead of your check.

Azja

Level 32 , Krakow, Poland

26 May 2019, 16:25

Delete if statement

if (d % 1 == 0)
break;

You might check if it is not double. When d is 2.0 you got true and break; occurs so alert method didn't happen but you want this. If d is 1.2 you get alert but if d is 1.0 it is double too but with that you don't use alert method