My code continues to display a & a (11 &14) instead of a & b (11 & 7)

Question about the task

Closest to 10

Java Syntax, Level 4, Lesson 4

Under discussion

Please help me understand why this is happening. :S

Write the displayClosestToTen method. The method should display the argument that is nearest to 10.
For example, given the numbers 8 and 11, 11 is closest to ten. If both numbers are equally close to 10, then display either of them.

Hint:
use the public static int abs(int a) method, which returns the absolute value of a number.

Requirements:

The program should display text on the screen.
The main method should not call System.out.println or System.out.print().
The main method should call the displayClosestToTen method.
The displayClosestToTen method should call the abs method.
The displayClosestToTen method should display a number on the screen in accordance with the task conditions.

package com.codegym.task.task04.task0409; /* Closest to 10 */ public class Solution { public static void main(String[] args) { displayClosestToTen(8, 11); displayClosestToTen(7, 14); } public static void displayClosestToTen(int a, int b) { // write your code here int c = (a - 10); abs(c); int d = (b - 10); abs(d); if (c < d) { System.out.println(abs(a)); } if (c > d) { System.out.println(abs(b)); } if (d == c) { System.out.println(abs(a) + abs(b)); } } public static int abs(int a) { if (a < 0) { return -a; } else { return a; } } }

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Isenraf

Level 20 , Douala, Cameroon

23 June 2019, 08:50

use else if/ else

tunde hammed

Level 4 , Ashton-under-Lyne, United Kingdom

23 June 2019, 07:50

Help! got stuck on this task: public class Solution { public static void main(String[] args) { displayClosestToTen(8, 11); displayClosestToTen(7, 14); } public static void displayClosestToTen(int a, int b) { // write your code here if (abs(a -10) > abs(b - 10)) { System.out.println(abs(b)); } else{ System.out.println(abs(a)); } } public static int abs(int a) { if (a < 0) { return -a; } else { return a; } } } I dont think I did anything wrong, but got error message "Be sure that the program works correctly with negative numbers."

Max

Level 6 , Minsk, Belarus

2 June 2019, 19:18

Why did you write this? if (d == c) { System.out.println(abs(a) + abs(b)); } Just think about this "then display either of them"

Mátyás Spitzner

Level 12 , Hungary

28 May 2019, 19:16

//May abs method should working on this way like this. public static void displayClosestToTen(int a, int b) { int c = abs(a - 10); int d = abs(b - 10); if (c < d) { System.out.println(a); } else { System.out.println(b); } }

Guadalupe Gagnon

Level 37 , Tampa, United States

28 May 2019, 03:20

add these lines of code to your program and see if you can figure out the issue:

public static void displayClosestToTen(int a, int b) {
        int c = (a - 10);
        System.out.println("The value of variable c is: " + c);  // add
        abs(c);
        System.out.println("The value of variable c after calling abs(c): " + c); // add
        int d = (b - 10);
        System.out.println("The value of variable d is: " + d); // add
        abs(d);
        System.out.println("The value of variable d after calling abs(d): " + d); // add

        if (c < d) {
            System.out.println(abs(a));
        }
        if (c > d) {
            System.out.println(abs(b));
        }
        if (d == c) {
            System.out.println(abs(a) + abs(b));
        }
    }

Ravien Sewpal Java Developer

28 May 2019, 18:52

I got the same problem, It keeps displaying 8 and 7... I think there's sth wrong with the abs method...

Guadalupe Gagnon

Level 37 , Tampa, United States

28 May 2019, 19:02

nothing is wrong with the abs method