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package com.codegym.task.task04.task0409; /* Closest to 10 */ public class Solution { public static void main(String[] args) { displayClosestToTen(8, 11); displayClosestToTen(7, 14); displayClosestToTen(7,13); } public static void displayClosestToTen(int a, int b) { int c = a - 10; int d = b - 10; if (abs(c) > abs(d)) System.out.println(b); if (abs(c) < abs(d)) System.out.println(a); if (abs(c) == abs(d)) System.out.println("either"); } public static int abs(int a) { if (a < 0) { return -a; } else { return a; } } }

Write the displayClosestToTen method. The method should display the argument that is nearest to 10.
For example, given the numbers 8 and 11, 11 is closest to ten. If both numbers are equally close to 10, then display either of them.

Hint:
use the public static int abs(int a) method, which returns the absolute value of a number.

Requirements:

The program should display text on the screen.
The main method should not call System.out.println or System.out.print().
The main method should call the displayClosestToTen method.
The displayClosestToTen method should call the abs method.
The displayClosestToTen method should display a number on the screen in accordance with the task conditions.

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MrNemO

Level 19 , Pale, Bosnia and Herzegovina

3 June 2019, 19:02

solution

Try to use abs() method when initialize int d and int c ( int d = abs(a - 10) ), not in if statements. And when you check is c and d equal , print only one number.

Profj

Level 20 , Lagos, Nigeria

10 June 2019, 17:47

" And when you check is c and d equal , print only one number." This worked out perfectly. Thanks