What am i missing?

Question about the task

Rule of the triangle

Java Syntax, Level 4, Lesson 4

Resolved

What am i missing?

Use the keyboard to enter three numbers a, b, and c (the lengths of the sides of the proposed triangle).
Determine whether a triangle with these sides can exist.
Display the result as follows:
"The triangle is possible." - if a triangle with these sides could exist.
"The triangle is not possible." - if a triangle with these sides cannot exist.

Hint:
A triangle can exist only if the sum of two of its sides is greater than the third side.
You need to compare each side with the sum of the other two.
If even one side is larger or equal to the sum of the other two sides, then no such triangle exists.

Requirements:

The program should read three numbers from the keyboard.
The program should display text on the screen according to the task conditions.
If a triangle with the specified sides could exist, you need to display: "The triangle is possible."
If a triangle with the specified sides cannot exist, you need to display: "The triangle is not possible."

package com.codegym.task.task04.task0415; /* Rule of the triangle */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(bufferedReader.readLine()); int b = Integer.parseInt(bufferedReader.readLine()); int c = Integer.parseInt(bufferedReader.readLine()); if ((a + b) <= c || (a + c) <= b || (b + c) <= a) System.out.println("The triangle is possible."); else System.out.println("The triangle is not possible."); } }

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Nitin raj

Level 12 , Mumbai, India

13 June 2019, 20:39

Simple chnage the comparison operator in if condition > because sum of two sides of a traingle always greater than the third side

parthasarathy t s

Level 6 , Mumbai, India

13 June 2019, 09:54

public static void main(String[] args) throws Exception { //write your code here BufferedReader scan=new BufferedReader(new InputStreamReader(System.in)); int a=Integer.parseInt(scan.readLine()); int b=Integer.parseInt(scan.readLine()); int c=Integer.parseInt(scan.readLine()); if((a+b>c)&&(b+c>a)&&(c+a>b)) System.out.println("The triangle is possible."); else System.out.println("The triangle is not possible.");

Durmus Gulbahar

Level 22 , Antalya, Turkey

5 June 2019, 16:27

if block must be "triangle not possible". You should change texts. if ((a + b) <= c || (a + c) <= b || (b + c) <= a) System.out.println("The triangle is possible."); -- THIS MEANS TRIANGLE NOT POSSIBLE IF ONE SIDE GREATER THAN OTHER TWO SIDES' SUM.

Kotlet

Level 28 , Wroclaw, Poland

5 June 2019, 11:18

It is probably because the task is to check if two sides are greater (< / >) than the other side. You checked if they are greater or equal (<= / >=). Therefore in your case the triangle with sides a= 2 b= 3 c=5 is possible, when in fact it is not.

ddi

Level 18 , Dortmund, Germany

5 June 2019, 13:45

I tried without the = signs and i still have this failure..

Kotlet

Level 28 , Wroclaw, Poland

6 June 2019, 12:08

solution

Ah yes, as durmusgulbahar wrote you either: change the output in the brackets ( because If even one side (for example c) is larger than the sum of the other two sides (a+b), then no such triangle exists):

if ((a + b) <= c || (a + c) <= b || (b + c) <= a)
            System.out.println("The triangle is not possible.");
        else
            System.out.println("The triangle is possible.");

or change the equation

if (a < b + c && b < a + c && c < b + a){
           System.out.println("The triangle is possible.");
       }
       else {
           System.out.println("The triangle is not possible.");
       }

EDIT: I rethinked why the first did not work out and actually I was wrong. There should be equal signs :) So the only wrong thing you did was changing the place of system out print (the messages). It is because the first method checks if a triangle is not possible. The second checks if it is possible. I run the first one in this state and it was approved. I just wanted to clarify :)

ddi

Level 18 , Dortmund, Germany

6 June 2019, 12:52

The second equation did the trick! Thanks