Why am I not catching the ArithmaticException?

Question about the task

Under discussion

package com.codegym.task.task09.task0919;

/*
Dividing by zero

*/

public class Solution {

    public static void main(String[] args) {
        try {
            divideByZero();
        }
        catch (Exception e) {
            e.printStackTrace();
        }
    }
    public static void divideByZero() {
        System.out.println(6/0);
    }
}

Create a public static void divideByZero method that divides any number by zero, and display the result of the division.
Wrap the divideByZero method call in a try-catch block. Display the exception stack trace using the exception.printStackTrace() method.

Requirements:

The class must have a public static void divideByZero method.
The divideByZero method must contain a divide-by-zero operation.
The divideByZero method should call System.out.println or System.out.print.
The main method must have a try-catch block.
The main method should catch any exceptions thrown by the divideByZero method.
The program should display the stack trace of the caught exception.

package com.codegym.task.task09.task0919; /* Dividing by zero */ public class Solution { public static void main(String[] args) { try { divideByZero(); } catch(Exception e) { e.printStackTrace(); } } public static void divideByZero() { System.out.println(6/0); } }

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CapLand

Level 23 , Mentor, United States

13 June 2019, 03:33

Nevermind, I figured out it is working properly. printStackTrace() shows up as red in the output when testing and makes it look like you aren't catching it. I was getting so frustrated.

Guadalupe Gagnon

Level 37 , Tampa, United States

12 November 2019, 16:43

good catch