I verified my solution....-20 // correct -40 // correct -30 // correct 40 // incorrect !!!....What do I do..? Please Help..!!!

Question about the task

Resolved

package com.codegym.task.task02.task0217;

/*
Minimum of four numbers

*/
public class Solution {
    public static int min(int a, int b, int c, int d) {
     min(a,b);

        if(c<=a && c<=b && c<=d)
        return c;
        else
        return d;

    }

    public static int min(int a, int b) {
     int c;
     if(a<b)
     c=a;
     else
     c=b;

      return c;

    }

    public static void main(String[] args) throws Exception {
        System.out.println(min(-20, -10));
        System.out.println(min(-20, -10, -30, -40));
        System.out.println(min(-20, -10, -30, 40));
        System.out.println(min(-40, -10, -30, 40));
    }
}

Write a function that computes the minimum of four numbers.
The function min(a, b, c, d) should use (call) the function min(a, b)

Hint:
You need to write the body of the two existing min functions.

Requirements:

The program should display text on the screen.
The min methods should not display text on the screen.
The main method should call min(a, b) and min(a, b, c, d).
The main method should display the result of the min methods. Each time, on a new line.
The min(a, b) method must return the minimum of the numbers a and b.
The min(a, b, c, d) method must use the min(a, b) method.
The min(a, b, c, d) method must return the minimum of the numbers a, b, c, and d.

package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { min(a,b); if(c<=a && c<=b && c<=d) return c; else return d; } public static int min(int a, int b) { int c; if(a<b) c=a; else c=b; return c; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }