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i try solve this with arrays, but i'm doing something wrong all the time, can someone tell me what should i do?

Write a program that:
1. reads a number N (must be greater than 0) from the console
2. reads N numbers from the console
3. Displays the maximum of the N entered numbers.

Requirements:

The program should read the numbers from the keyboard.
The program must display a number on the screen.
The class must have a public static void main method.
Don't add new methods to the Solution class.
The program should display the maximum of the N entered numbers.
The program should not display anything if N is less than or equal to 0.

package com.codegym.task.task05.task0532; import java.io.*; import java.util.Arrays; import java.util.Scanner; /* Task about algorithms */ public class Solution { public static void main(String[] args) throws Exception { /* BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); String sN = reader.readLine(); int N = Integer.parseInt(sN);*/ Scanner sc = new Scanner(System.in); int N = sc.nextInt(); int maximum = 0; int count = 0; //write your code here if (N > 0) { count++; int[] numbers = {N}; for (int i = 0; i < count; i++) { if (numbers[i] < numbers[i+1]){ maximum = numbers[i+1]; } } } System.out.println(maximum); } }

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Dmitriy Bursa

Level 27 , Kyiv, Ukraine

30 July 2019, 08:45

first, you need read N as count of numbers and after you must to read from the console 'N' numbers i.e. N=5 need 5 numbrers read from the console in the loop your 'FOR' is performed 1 time, becouse count=1 (count++ 1 time) try this: when you read N,

int maximum = 0;

after use loop

for (int i = 0; i < N; i++) {
    int m = sc.nextInt();
   if maximum < m {maximum = m;}
}
// display maximum