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Question about the task

Splitting a file

Java Core, Level 8, Lesson 5

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The second half of the bytes in the first file must be written to the third file??

Read 3 file names from the console: file1, file2, file3.
Split file1 as follows:
Write the first half of its bytes to file2,and write the second half of its bytes to file3.
If the number of bytes in file1 is odd, then file2 should contain the larger half.
Close the streams.

Requirements:

The program should read a file name three times from the console.
Use FileInputStream to read from a file, and use FileOutputStream to write to files.
The first half of the bytes in the first file must be written to the second file.
The second half of the bytes in the first file must be written to the third file.
The FileInputStream and FileOutputStream must be closed.

package com.codegym.task.task18.task1808; /* Splitting a file */ import java.io.*; import java.util.ArrayList; public class Solution { public static void main(String[] args) throws IOException { BufferedReader rd = new BufferedReader(new InputStreamReader(System.in)); String file1 = rd.readLine(); String file2 = rd.readLine(); String file3 = rd.readLine(); rd.close(); FileInputStream inputStream = new FileInputStream(file1); FileOutputStream outputStream2 = new FileOutputStream(file2); FileOutputStream outputStream3 = new FileOutputStream(file3); byte[] buffer = new byte[1000000]; while (inputStream.available() > 0) { int count = inputStream.read(buffer); if ((count % 2) == 0) { outputStream2.write(buffer, 0, count / 2); outputStream3.write(buffer,count / 2, count); } else { outputStream2.write(buffer, 0, (count / 2) + 1); outputStream3.write(buffer,(count / 2) + 1, count); } } inputStream.close(); outputStream2.close(); outputStream3.close(); } }

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MICHAEL DUNLAP

Level 20 , Bellevue, United States

29 September 2019, 05:47

A trick to this can involve letting java throw away the remainder of a simple division. For instance 33 / 2, with both numerals as integers, results in an integer (the remainder is discarded). For the first file this is perfect because with an odd number of bytes, the first file gets the fewer bytes anyway. So you can simply construct a while loop that reads each line of the source file and adds that line to the first file if the number of available bytes is greater than or equal to the total count of bytes divided by 2. If you go this route, initialize a variable with inputStream.available() before the while loop.