where correction is necessary

Resolved

public static void main(String[] args) {
      Thread.sleep(1000);
      for (int i = 30; i >= 0; i--) {
          System.out.println(i);
          Thread.sleep(1000);
          //write your code here
      }

      System.out.println("Boom!");
  }

Comments (8)

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Baljinder Singh

Level 20 , Toronto, Canada

24 September 2018, 01:01

useful

Add Exception to the method signaature

public static void main(String[] args) throws InterruptedException {

gery

Level 9 , Islamabad, Pakistan

24 September 2018, 01:19

where to put correction for thread must repeat 31 times.

for (int i = 30; i >= 0; i--) {
            System.out.println(i);
            Thread.sleep(100);
            //write your code here
        }
         Thread.sleep(100);
        System.out.println("Boom!");

gery

Level 9 , Islamabad, Pakistan

24 September 2018, 01:24

for (int i = 30; i >= 0; i--) {
    System.out.println(i);
    if(i==10)
    {
        Thread.sleep(100);
    }
    Thread.sleep(100);
    //write your code here
}

gery

Level 9 , Islamabad, Pakistan

24 September 2018, 01:35

but requirement states that the count must be from 30 to 0. i just ran it and it throws this requirement didnt met

gery

Level 9 , Islamabad, Pakistan

24 September 2018, 01:35

for (int i = 31; i >= 0; i--) {
            System.out.println(i);
            /*if(i==10)
            {
                Thread.sleep(100);
            }*/
            Thread.sleep(100);
            //write your code here
        }

Baljinder Singh

Level 20 , Toronto, Canada

24 September 2018, 01:43

solution

for (int i = 30; i >= 0; i--) {
    System.out.println(i);
    Thread.sleep(1000);
}
System.out.println("Boom!");

gery

Level 9 , Islamabad, Pakistan

24 September 2018, 00:46

* here line 2 &5 shows error

gery

Level 9 , Islamabad, Pakistan

24 September 2018, 00:45

it shows error on line 12 & 15;