Any help please?

Question about the task

Even and odd digits

Java Syntax, Level 6, Lesson 5

Under discussion

Cant figure out the rest .

Use the keyboard to enter a positive number. Determine the number of even digits and odd digits in the entered number.
If a number is divisible by 2 without a remainder (i.e. the remainder is zero), then it is even.
And we'll increase the even digit counter (static variable even) by 1.
Otherwise, the number is odd, so we'll increase the odd digit counter (static variable odd).
Display the following message: "Even: a Odd: b", where a is the number of even digits and b is the number of odd digits.

Example for 4445:
Even: 3 Odd: 1

Requirements:

The program must read data from the keyboard.
The main method should calculate how many even digits are in the entered number and then write this number to the variable even.
The main method should calculate how many odd digits are in the entered number and then write this number to the variable odd.
The program should display text on the screen.
The displayed text must match the task conditions.

package com.codegym.task.task06.task0606; import java.io.*; import java.util.*; /* Even and odd digits */ public class Solution { public static int even; public static int odd; public static void main(String[] args) throws IOException { Scanner sc = new Scanner(System.in); int num = sc.nextInt(); if (num%2==0){ even++; }else{ odd++; } System.out.println("Even: "+even+" Odd: "+odd); } }

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Anthony Chalk

Level 30 , London, United Kingdom

28 October 2019, 11:54

What you're doing is determining if the number is even or odd, you need to do that for each digit of the number. You can divide the number by 10 and then see if the remainder is odd or even. Use a loop to go through every digit of the number.