com.codegym.task.task13.task1305.Solution.Dream is abstract; cannot be instantiated. file com/codegym/task/task13/task1305/Solution.java, line 12, position 165

Question about the task

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cannot be instantiated because it is abstract but it's not abstract. public class Solution { public static void main(String[] args) { System.out.println(new Dream().HOBBY.toString()); System.out.println(new Hobby().toString()); } interface Desire { } public static interface Dream { public static Hobby HOBBY = new Hobby(); } static class Hobby implements Dream, Desire { static int INDEX = 1; @Override public String toString() { INDEX++; return "" + INDEX; } } }

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Guadalupe Gagnon

Level 37 , Tampa, United States

4 November 2019, 15:20

Abstract means that the particular object can be be declared but cannot be instantiated. Interfaces are abstract by definition. Code like this will not work:

// ↓ this is a declaration
Desire test = new Desire();
             //  ↑ this is an instantiation

While code like this is perfectly acceptable:

Desire test = new Hobby();
// Desire is an interface and therefore cannot be directly instantiated
// but an object of type Desire can be declared and then instantiated
// to an actual object that implements (or extends) the abstract object

In the code you linked above, the line that is causing problems is "System.out.println(new Dream().HOBBY.toString());" specifically the new Dream() part. That is because it is trying to create an object out of an interface (which is abstract). Because the variable HOBBY in the interface is static, you can access it without creating an object. Try doing this.

Steve Bennett

Level 18 , Stoneleigh

17 November 2020, 16:53

You always give the best answer, not the exact answer but enough to solve! Helped me straight out, thanks !!