SoS

Question about the task

Under discussion

Any reasons to why my reference idea cannot call to the getDescription method? The printIDEA is in the Solutions class and not the IDEA class. By the way, if you can, can you briefly summarize what the methods are doing? Is the printIDEA method calling to the getDescription method to return the String value and print it out in the main method? Thanks!

1. In the Solution class, create the public static Idea class
2. In the Idea class, declare a public String getDescription() method that returns any non-empty string
3. In the Solution class, create a static public void printIdea(Idea idea) method that will display a description of the idea (what the getDescription method returns)

Requirements:

In the Solution class, create the public static Idea class.
In the Idea class, create the public String getDescription() method.
The getDescription method must return any non-empty string.
In the Solution class, create a public static void printIdea(Idea idea) method.
The printIdea method should display the idea description on the screen.

package com.codegym.task.task06.task0617; /* Notepad for new ideas */ public class Solution { public static class Idea { String a; public String getDescription(){ return "string"; } } public static void printIdea(Idea idea){ System.out.println(idea.getDescription); } public static void main(String[] args) { printIdea(new Idea()); } //write your code here }

Comments (4)

Popular
New
Old

You must be signed in to leave a comment

Guadalupe Gagnon

Level 37 , Tampa, United States

6 November 2019, 19:33

useful

getDescription is a method and, even though there are no parameters, must be called using method parameters. Add parentheses to the end of the method call on line 18. The way that this works is: #1 when a program is started the main method is called. This is the entry point of the program. The (String[] args) would contain any command line arguments (they will go over this in later lessons). Your program will start at the first line in this method. #2 Line 22, being the first line, is a method call that is defined at line 18: public static void printIdea(Idea idea) where 'public' is its access level, 'static' declares that this method can be called without using an object, 'void' is its return value which means it doesn't return anything, 'printIdea' is the method name and is used to call the method with the method parameters (Idea idea). The correct parameters must be used when calling the method, which line 22 does correctly. #3 code jumps to the method called and starts on the first line in the method, which is line 18. This is a call to the println() method which will output whatever is contained in the parameters to the console with few restrictions. Any parameter that is itself a method will process before the outer method processes, this is important to remember as it is a rule. This method contains a method as a parameter, getDescription(), and that will process before the call to println(). #4 Code jumps to the getDescription() method which is a public method that returns a String. The String that this method returns is on line 13. #5 code returns to line 18 after the inner method 'getDescription()' resolves, and it will not output to the screen the string that is getDescription(). #6 code returns to the line after 22 and continues #7 no code remains so program ends.

Jimmy Phan

Level 7 , Atlanta, United States

7 November 2019, 17:25

Extremely detailed reply. Thank you very much for the clarification!

Guadalupe Gagnon

Level 37 , Tampa, United States

7 November 2019, 17:48

I guess i missed the "briefly" part of your second request. Ooops.

Jimmy Phan

Level 7 , Atlanta, United States

7 November 2019, 19:27

Oh no, trust me, this was so helpful I had to write it down in my notes lol. I'm glad you're basically telling me where the codes are running and in which manner. Hopefully others will be able to see your explanation as well.