I am not able to satisfy last condition,plzz help

Question about the task

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package com.codegym.task.task10.task1019; import java.io.*; import java.util.*; public class Solution { public static void main(String[] args) throws IOException { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); HashMap<String,Integer> map = new HashMap<String,Integer>(); //int id = Integer.parseInt(reader.readLine()); //String name = reader.readLine(); while(true) { Integer id = Integer.parseInt(reader.readLine()); if(id== 0) break; String name = reader.readLine(); if(name.isEmpty() && id!= 0){ System.out.println(id); break; }else if(!name.isEmpty()&& id!=0){ map.put(name,id); } } for(Map.Entry<String,Integer> entry : map.entrySet()){ System.out.println(entry.getValue() +" "+ entry.getKey()); } } }

Task: The program reads a pair (a number and string) from the keyboard and displays it on the screen.
New task: The program reads pairs (a number and string) from the keyboard and stores them in a HashMap.
Any empty input signifies the end of data entry.
The numbers can be repeated.
The strings are always unique.
The entered data must not be lost!
The program then displays the contents of the HashMap on the screen.
Each pair on a new line.

Example input:
1 Sam 2 I 1 Am

Example output:
1 Sam 2 I 1 Am

Requirements:

The program must read data from the keyboard.
The program should display text on the screen.
In the main method, declare a HashMap variable and immediately initialize it.
The program should put the pairs read from the keyboard into the HashMap.
The program should display the contents of the HashMap in accordance with the conditions. The key and value are separated by a space. Each value should be on a new line.

package com.codegym.task.task10.task1019; import java.io.*; import java.util.*; /* Functionality is not enough! */ public class Solution { public static void main(String[] args) throws IOException { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); HashMap<String,Integer> map = new HashMap<String,Integer>(); //int id = Integer.parseInt(reader.readLine()); //String name = reader.readLine(); while(true) { Integer id = Integer.parseInt(reader.readLine()); if(id== 0) break; String name = reader.readLine(); if(name.isEmpty() && id!= 0){ System.out.println(id); break; }else if(!name.isEmpty()&& id!=0){ map.put(name,id); } } for(Map.Entry<String,Integer> entry : map.entrySet()){ System.out.println(entry.getValue() +" "+ entry.getKey()); } } }

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Bipin kanani

Level 11 , Ahmedabad, India

8 September 2020, 12:13

run this code and your task will pass. public class Solution { public static void main(String[] args) throws IOException { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); HashMap<String, Integer> map = new HashMap<String, Integer>(); try{ while(true){ String x=reader.readLine(); if(x.isEmpty()) break; int id=Integer.parseInt(x); String name=reader.readLine(); if(name.isEmpty()){map.put("",id); break;} map.put(name,id); } }catch(NullPointerException e){System.out.println(e);} for(Map.Entry<String,Integer> entry : map.entrySet()){ System.out.println(entry.getValue()+" "+entry.getKey()); } } }

Guadalupe Gagnon

Level 37 , Tampa, United States

20 November 2019, 15:08

Line 21 will not work as empty or null input will throw an exception and crash the program.

Mateusz haszyaz

Level 12 , Wroclaw, Poand

21 December 2019, 20:25

yep try this line write in try-catche block try { } catch(Exception err) { }