square of number

Question about the task

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I do not understand why the system.out.println(sqr(5)); part is so early in the code? why isn't it at the end instead of being in the main method? I am asking be cause the a*a part comes after the print statement..so how is it printing before it gets the answer??? maybe I am looking at this the wrong way

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Anonymous #11474101

Level 1 , Thailand

19 February, 14:24

Thank

Tyler Begrow

Level 7 , United States

14 January 2020, 03:34

useful

This is because the main method is the entry point for your program. It takes priority over everything else. They could have put the sqr() method before main and the answer would be the same. The important part is that the sqr() method is defined so the main method can call it and then complete the rest of the tasks that are in main. Think of it like a detour.

Jo88

Level 4 , Boston, United States

14 January 2020, 04:18

thanks!

Tyler Begrow

Level 7 , United States

14 January 2020, 21:15

You're welcome!