I don't understand what is wrong with the text I output

Question about the task

Come on, lucky seven!

Java Syntax, Level 4, Lesson 4

Resolved

What am I missing?

Write the checkInterval method. The method should check whether an integer is in the range from 50 to 100 and display the result on the screen as follows: "The number a is not in the interval." or "The number a is in the interval.", where a is the method argument.

Example for 112:
The number 112 is not in the interval.

Example for 60:
The number 60 is in the interval.

Requirements:

The program should display text on the screen.
The main method should not call System.out.println or System.out.print().
The main method must call the checkInterval method.
The checkInterval method must be static void.
The checkInterval method should display text on the screen in accordance with the task conditions.

package com.codegym.task.task04.task0410; /* Come on, lucky seven! */ public class Solution { public static void main(String[] args) { checkInterval(60); checkInterval(112); checkInterval(10); } public static void checkInterval(int a) { if (a >= 60 && a <= 100) { System.out.println("The number " + a + " is in the interval."); } else { System.out.println("The number " + a + " is not in the interval."); } } }

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Barkha Mishra Java Developer at Evosys

3 August 2019, 07:53

a>=50 is correct a>=60 is not correct(as is written in the code).

User

Level 5 , Shymkent, Kazakhstan

18 June 2019, 13:31

public static void checkInterval(int a) { if (a<=100 && a=>50){ System.out.println("The number " + a +" is in the interval."); } else{ System.out.println("The number " + a + " is not in the interval."); } }

Okanlawon Oluwatobi Damilare

Level 9 , Banjul, Gambia

18 March 2019, 17:10

if(a >= 50 && a <= 100){ System.out.println("The number "+ a +" is in the interval."); }else System.out.println("The number "+ a +" is in not the interval.");

fareed

Level 11 , Bulandshahr, India

23 December 2018, 09:46

try if(a<=100 && a>=50) System.out.println("The number " +a+ " is in the interval."); else System.out.println("The number " +a+ " is not in the interval.");