I've tried everything I can think of!

Question about the task

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Sorry guys, I'm still not so good at this stuff as I should be by this level. But I need to get past this task! Don't understand that second last condition. (And yes, partly borrowed code is pasted in kinda messy so forgive me for that! I put hours into trying to figure it out still.)

Read a file name from the console.
Replace the main method's System.out object with your own reader wrapper similar to the one shown in the lesson.
Your reader wrapper must output all text to both the console and a file whose name you have read.
Call testString's existing printSomething() method.
Restore the System.out variable back to the original stream.
Close the file stream.

Example of screen output:
This is text for testing

Example file content:
This is text for testing

Requirements:

The Solution class must contain a TestString class.
The Solution class must have a public static TestString field called testString that is initialized immediately.
The TestString class must have a public void printSomething() method.
The TestString class's printSomething() method must display "This is text for testing".
In the main(String[] args) method, the program must read file names from the console (use BufferedReader).
In the main(String[] args) method, the BufferedReader used for reading input from the console must be closed after use.
The Solution class's main(String[] args) method must create a PrintStream object (use the PrintStream constructor with a ByteArrayOutputStream parameter).
The Solution class's main(String[] args) method should replace and then restore the console output stream (System.out).
The Solution class's main(String[] args) method must call testString's printSomething() method once.
The Solution class's main(String[] args) method must write the output of the printSomething() method to both the console and the file (use FileOutputStream).
The file output stream (FileOutputStream) must be closed.

package com.codegym.task.task19.task1915; /* Reader Wrapper 2 */ import java.io.*; public class Solution { public static TestString testString = new TestString(); public static void main(String[] args) throws IOException { BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in)); String file = bufferedReader.readLine(); bufferedReader.close(); PrintStream consoleStream = System.out ; ByteArrayOutputStream outputStream = new ByteArrayOutputStream(); FileOutputStream fileOutputStream = new FileOutputStream(file); PrintStream stream = new PrintStream(outputStream); System.setOut(stream); testString.printSomething(); String result = outputStream.toString(); System.setOut(consoleStream); outputStream.close(); fileOutputStream.close(); } public static class TestString { public void printSomething() { System.out.println("This is text for testing"); } } }

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MaGaby2280

Level 41 , Guatemala City, Guatemala

31 March 2020, 23:50

This what worked for me: String result = outputStream.toString(); System.setOut(consoleStream); byte[] bytes = result.getBytes(); fileOutputStream.write(bytes); consoleStream.write(bytes);

KIN SOCHEAT

Level 34 , Phnom Penh, Cambogia

10 March 2020, 04:00

PrintStream consoleStream = System.out ; ByteArrayOutputStream outputStream = new ByteArrayOutputStream() PrintStream stream = new PrintStream(outputStream); System.setOut(stream); testString.printSomething();

jamylam

Level 26 , Nairobi, Kenya

28 February 2020, 13:27

solution

In line 24 you already Converted the data written to the ByteArray into a string. In order to write that string to the fileoutputstream, convert to a byte[] i.e byte[] bytes = .... Procced to write those bytes in fileOutputStream as well as in the consoleStream. example fileOutputStream.write(bytes);

Tian Pro

Level 23 , Cape Town, South Africa

2 March 2020, 06:51

Woah, awesome explanation! Thank you so much :D Learned quite a bit from this. Felt like completely uncharted territory for me before haha