o is not a negative or positive number?

Question about the task

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public static int count=0; public static void main(String[] args) throws Exception { //write your code here InputStream ab= System.in; InputStreamReader bd= new InputStreamReader(ab); BufferedReader a= new BufferedReader(bd); String ah= a.readLine(); String hj= a.readLine(); String yu= a.readLine(); int h = Integer.parseInt(ah); int d= Integer.parseInt(hj); int o= Integer.parseInt(yu); if(h==0 & d==0 & o==0) {System.out.println(0);} if(h>0){count++;} if(d>0){count++;} if (o>0){count++;} System.out.println(count);

Use the keyboard to enter three integers. Display the number of positive numbers in the original set.

Here are some examples:
a) if you enter the numbers
-4
6
6
then we display
2

b) if you enter the numbers
-6
-6
-3
then we display
0

c) if you enter the numbers
0
1
2
then we display
2

Requirements:

The program should read the numbers from the keyboard.
The program must display a number on the screen.
The program should display the number of positive numbers in the original set.
If there are no positive numbers, the program should display "0".
Note that 0 is not a positive or negative number.

package com.codegym.task.task04.task0428; /* Positive number */ import java.io.*; public class Solution { public static int count=0; public static void main(String[] args) throws Exception { //write your code here InputStream ab= System.in; InputStreamReader bd= new InputStreamReader(ab); BufferedReader a= new BufferedReader(bd); String ah= a.readLine(); String hj= a.readLine(); String yu= a.readLine(); int h = Integer.parseInt(ah); int d= Integer.parseInt(hj); int o= Integer.parseInt(yu); if(h==0 & d==0 & o==0) {System.out.println(0);} if(h>0){count++;} if(d>0){count++;} if (o>0){count++;} System.out.println(count); } }

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satya vath

Level 9 , Mumbai, India

30 October 2018, 12:42

package com.codegym.task.task04.task0428; /* Positive number */ import java.io.*; //use this code to get it public class Solution { public static void main(String[] args) throws Exception { //write your code here BufferedReader buf = new BufferedReader(new InputStreamReader(System.in)); String a = buf.readLine(); String b = buf.readLine(); String c = buf.readLine(); int d = Integer.parseInt(a); int e = Integer.parseInt(b); int f = Integer.parseInt(c); int count = 0; if (d > 0) { count++; } if (e > 0) { count++; } if (f > 0) { count++; } System.out.println(count); } }

muhammad asad ali

Level 5 , Islamabad, Pakistan

21 October 2018, 05:51

i apply zero it only give 1 time 0

Khurram

Level 16 , Lahore, Pakistan

21 October 2018, 05:05

if all the inputs are 0, your code prints 0 twice, instead of displaying 0 in line 25, try making the count variable 0, and then display it in line 29 once

Jakub M

Level 32 , Ostrava, Czech Republic

19 May 2020, 05:47

Correct, line 25 seems to be redundant:

if(h==0 & d==0 & o==0)  {System.out.println(0);}