Don't really understand.

Question about the task

Sum of the digits of a three-digit number

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I didn't really understand the problem in the first place, I attempted, tried to listen to the mentor suggestion, but I just am not getting it. Can someone explain what I gotta do? I don't want a straight answer, I like to problem solve and just need to understand the problem better. Thanks for your help y'all!

Write the code for sumDigitsInNumber(int number). The method takes a three-digit whole number. You need to calculate the sum of the digits of this number, and then return the result.

Consider this example:
The sumDigitsInNumber method is called with the argument 546.

Example output:
15

Requirements:

The program must not read data from the keyboard.
The sumDigitsInNumber(int) method must be public and static.
The sumDigitsInNumber method must return an int.
The sumDigitsInNumber method should not display anything.
The sumDigitsInNumber method must return the sum of all digits in the parameter number.

package com.codegym.task.task01.task0132; /* Sum of the digits of a three-digit number */ public class Solution { public static void main(String[] args) { System.out.println(sumDigitsInNumber(546)); } public static int sumDigitsInNumber(int number) { //write your code here int number1 = 500; int sum1 = number1/100; int number2 = 40; int sum2 = number2/10; int number3 = 6; int sum3 = number3/1; int sum = sum1 + sum2 + sum3; return sum; } }

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Samantha

Level 4 , Crofton, United States

9 April 2020, 13:36

Oh, Anna, I the % sign is that a precent of the number or does it mean something else in this context?

Angel Li

Level 18 , Fremont, United States

30 May 2020, 18:46

The % means mod, which is returning the remainder of two numbers.

giuse

Level 8 , Turin, Italy

8 April 2020, 18:28

useful

Hi, you have to pass an argument in the sumDigitsInNumber(int number) method. So you can't declare 3 variables inside the method, but you have to get a number and "split" it, in this case, from 546 to 54 and get 6 of rest, then from 54 to 5 and get 4 of rest etc...

hidden #10550504

Level 10

8 April 2020, 18:25

solution

public static int sumDigitsInNumber(int number) { int x = 0; while (number > 0) { x = x + number % 10; number = number /10; }return x; }