"Too Many Lines" (???)

Question about the task

Under discussion

Hey folks! I'm getting "The program displays too many lines" error, but I've tested using a real file using all sorts of characters and it shows exactly what it's suppose to show. Any hints? Thanks!

1. Read a file name from the console.
2. Read a set of numbers from the file.
3. Display only the even numbers, sorted in ascending order.

Example input:
5 8 -2 11 3 -5 2 10

Example output:
-2 2 8 10

Requirements:

The program must read data from the console.
The program must create a FileInputStream using the line read from the console.
The program should display data on the screen.
The program should display all of the even numbers read from the file, sorted in ascending order.
The program must close the input stream used to read the file (FileInputStream).

package com.codegym.task.task13.task1326; /* Sorting even numbers from a file */ import java.io.*; import java.lang.reflect.Array; import java.util.ArrayList; import java.util.Collections; public class Solution { public static void main(String[] args) throws IOException { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); String name = reader.readLine(); FileInputStream file= new FileInputStream(name); ArrayList<Integer> even = new ArrayList<>(); int ch; while((ch=file.read())!=-1) { if (Character.isDigit(ch)) { even.add(Character.getNumericValue(ch)); } } file.close(); reader.close(); // Collections.sort(even); for (int i=0; i<even.size(); i++ ) { if (even.get(i)%2==0){ System.out.println(even.get(i)); } } } }

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Angelica Backend Developer

10 September 2022, 18:17

BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); String file = reader.readLine(); InputStream inStream = new FileInputStream(file); BufferedReader seiLa = new BufferedReader(new InputStreamReader(inStream)); List<Integer> sortedNumbers = new ArrayList<>(); while (seiLa.ready()) { int number = Integer.parseInt(seiLa.readLine()); if (number % 2 == 0) sortedNumbers.add(number); } Collections.sort(sortedNumbers); for (int number : sortedNumbers) { System.out.println(number); } reader.close(); inStream.close(); }

KIN SOCHEAT

Level 34 , Phnom Penh, Cambogia

10 April 2020, 07:46

try{ int ch; while((ch=file.read())!=-1) { if (Character.isDigit(ch)) { even.add(Character.getNumericValue(ch)); } } file.close(); reader.close(); }catch (Exception e){ System.out.println(e); }

KIN SOCHEAT

Level 34 , Phnom Penh, Cambogia

10 April 2020, 07:40

the correct is d:\\doc.txt -2 2 8 10

KIN SOCHEAT

Level 34 , Phnom Penh, Cambogia

10 April 2020, 07:38

your result is d:\\doc.txt 0 2 2 8

Pablo Souza

Level 22 , Brisbane, Australia

10 April 2020, 04:54

ArrayList<Integer> evenNumbers = new ArrayList<>();

        FileInputStream inputStream = new FileInputStream(new BufferedReader(new InputStreamReader(System.in)).readLine());
        BufferedReader input = new BufferedReader(new InputStreamReader(inputStream));

        String x;
        while ((x= input.readLine()) != null) {
            int n = Integer.parseInt(x);
            if (n % 2 == 0) {
                evenNumbers.add(n);
            }
        }

        input.close();
        inputStream.close();

        Collections.sort(evenNumbers);

        for (Integer n: evenNumbers) {
            System.out.println(n);
        }

This passed, but on IntelliJ I'm still getting an error when I try negative numbers:

Exception in thread "main" java.lang.NumberFormatException: For input string: "1234 -1 -2 -3"
	at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
	at java.lang.Integer.parseInt(Integer.java:580)
	at java.lang.Integer.parseInt(Integer.java:615)
	at com.codegym.task.task13.task1326.Solution.main(Solution.java:25)