whats wrong with my code

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package com.codegym.task.task04.task0424; /* Three numbers */ import java.io.*; import java.util.Scanner; public class Solution { public static void main(String[] args) throws Exception { //write your code here Scanner sc=new Scanner(System.in); int a=sc.nextInt(); int b=sc.nextInt(); int c=sc.nextInt(); int arr[]=new int [4]; for(int i=0;i<arr.length;i++){ arr[0]=a; arr[1]=b; arr[2]=c; } if((arr[1]==arr[2])&&(arr[1]!=arr[3])){ System.out.println(3); } else if((arr[2]==arr[3])&&(arr[2]!=arr[1])){ System.out.println(1); } else if((arr[3]==arr[1])&&(arr[3]!=arr[2])){ System.out.println(2); } else{ } } }

Use the keyboard to enter three integers. One of the numbers is unique. The other two are identical. Display the ordinal number of the number that is different from the others.

Example for 4 6 6:
1

Example for 6 6 3:
3

Requirements:

The program should read the numbers from the keyboard.
The program should use System.out.println() or System.out.print().
The program should display the ordinal number of the number that is different from the others.
If all the numbers are different, don't display anything.

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Lawrence Babay

Level 6 , Rockville, United States

21 April 2020, 00:25

just in case you haven't resolve this challenge. you might wanna remove the arrays and rewrite the logic. 2nd hint: else if(b != c && a == c) { System.out.println(2);

horst

Level 26 , Not in list

10 April 2020, 11:50

First of all: It's a nice idea, but you don't have to put all the values inside an array. At the moment, your code doesn't output the right answer because you access the wrong indices of the array. (Don't worry, its a classic!) In lines 20-22 you correctly put a at index 0, b at index 1 and c at index 2. However, in your if-else-if-statements, you are accessing indices 1, 2 and 3. (the number at index 3 is always zero, by the way, because your array-length is 4 and the fourth element (at index 3!) is never assigned a value, thereby still having the default value 0). You can fix this by using indices 0, 1 and 2. But you can also completely get rid of the array and simply write something like this:

if (a == b && a != c) {
                 System.out.println(3);
             } // and so on...