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Question about the task

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what we code in different place and why

Write a function that computes the minimum of four numbers.
The function min(a, b, c, d) should use (call) the function min(a, b)

Hint:
You need to write the body of the two existing min functions.

Requirements:

The program should display text on the screen.
The min methods should not display text on the screen.
The main method should call min(a, b) and min(a, b, c, d).
The main method should display the result of the min methods. Each time, on a new line.
The min(a, b) method must return the minimum of the numbers a and b.
The min(a, b, c, d) method must use the min(a, b) method.
The min(a, b, c, d) method must return the minimum of the numbers a, b, c, and d.

package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { //write your code here int m; if (a<b) (m=a); return a; } public static int min(int a, int b) { //write your code here int m; if (c<a&&d<c) (m=d); return m; else (d>c) (m=c); return m; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

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Nouser

Level 36 , Germany

27 April 2020, 20:05

Hi, you're mixing up things. One function just calculates the minimum of two numbers (min(a, b)). There's no need to use other variables than a and b here.The other should output the minimum of four numbers. Here you have to use all four variables a to d. Let's start with the minimum of two numbers. That's pretty easy. If a < b, then return a, otherwise b (in this task you don't have to check if they are equal) Then to the minimum of four function. You can call the minimum of two function three times to get the result.